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damaskus [11]
2 years ago
5

What is the area of the shaded region? 21 mm 24 mm 42 mm 48 mm Save and Exit

Mathematics
1 answer:
Harrizon [31]2 years ago
6 0

Answer:

It seems that you have missed to upload the shaded region for this problem. you are requested to please provide the shaded region so that we can help you with this problem

Step-by-step explanation:

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What is the midpoint of the line whose end points are (5,9) and (-3,7).
AysviL [449]
Midpoint= \frac{x_{2}+ x_{1}}{2} ,  \frac{y_{2}+ y_{1}}{2}
              = \frac{5+(-3)}{2} ,  \frac{9+7}{2}
              = 1, 8
5 0
3 years ago
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Which undefined geometric term is described as a location on a coordinated plane that designated by an ordered pair,(x,y)?
zepelin [54]

undefined slope = (16,3), ( 16, -80)


4 0
3 years ago
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Given g(x) = :-2 +4, solve for a when g(x) = 0.
evablogger [386]

Answer:

-7/4

Step-by-step explanation:

You are looking for the composite g(f(2)). The simplest way to solve this is to evaluate f(2) and enter the solution in to your g function.

g(f(2))=g(-(2)^2-2(2)+4)=g(-4-4+4)=g(-4)

g(-4)=4/(-4(-4)-2)=4/(16-2)=4/14=2/7

Therfor, g(f(2))=2/7  **I'm assuming the -4x-2 is all in the denominator of the g(x) function. If -2 is not in the denominator you would have

g(f(2))=4/(-4(-4)) -2=4/16 -2=1/4 -2=1/4-8/4= -7/4

8 0
3 years ago
What is the equation of a line that passes through (1,5) and (3,11)? Show work please.
jekas [21]
First, find the gradient/slope:
Use slope formula:
m=(y2-y1)/(x2-x1)
=(11-5)/(3-1)
=6/2
=3
Then use the line equation formula:
y=mx+c
You can substitute (1,5) if you like, also must substitute the slope as well!
5=3x1+c
c=2
Then find the full equation, which gives you the answer:
y=3x+2
3 0
3 years ago
Rob and Matt made 55 cups of lemonade
notka56 [123]

Answer:

Rob made 31, and Matt made 24

Step-by-step explanation:

55 in total

Rob made 7 more do 55 - 7 = 48

48 / 2 = 24

24 for Matt

24 +7 = 31

31 for rob

5 0
2 years ago
Read 2 more answers
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