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damaskus [11]
2 years ago
5

What is the area of the shaded region? 21 mm 24 mm 42 mm 48 mm Save and Exit

Mathematics
1 answer:
Harrizon [31]2 years ago
6 0

Answer:

It seems that you have missed to upload the shaded region for this problem. you are requested to please provide the shaded region so that we can help you with this problem

Step-by-step explanation:

You might be interested in
Express each number as a product of its prime factor of 39
vitfil [10]
If you just mean the product of the prime factors of 39 then this is the answer

39 = 3 x 13
5 0
3 years ago
Solve the equation using square roots. X^2+16=0
alexgriva [62]

Answer:

<u>The answer is :</u>

<u>x₁ = 4</u>

<u>x₂ = -4</u>

Step-by-step explanation:

Let's solve the equation using square roots.

X^2+16=0

x² + 16 = 0

x² = -16 (Adding 16 at both sides of the equation)

√x² = i√16 (Square root to both sides of the equation)

x = +/- 4i (Roots of the solution)

<u>x₁ = 4i</u>

<u>x₂ = -4i</u>

5 0
3 years ago
Read 2 more answers
What is the fourth term in the binomial expansion of (2x – y) 7?
nata0808 [166]

Answer:

(7C4) (2x)^4 (-y)^{7-4}

And replacing we got:

35 (2^4) x^4 (-y)^{-3}

And then the final term would be:

-560 x^4 y^3

Step-by-step explanation:

For this case we have the following expression:

(2x-y)^7

And we can use the binomial theorem given by:

(x+y)^n =\sum_{k=0}^n (nCk) x^k y^{n-k}

And for this case we want to find the fourth term and using the formula we have:

(7C4) (2x)^4 (-y)^{7-4}

And replacing we got:

35 (2^4) x^4 (-y)^{-3}

And then the final term would be:

-560 x^4 y^3

8 0
2 years ago
PLEASE HELP MEEE
antoniya [11.8K]

Answer:

(6a-4)°=(2a+68)°

6a-2a=68+4

4a=72

a=72/4

a=18

6 0
2 years ago
Read 2 more answers
In the June 2007 issue, Consumer Reports also examined the relative merits of top-loading and front-loading washing machines, te
saveliy_v [14]

Answer:

Yes

Step-by-step explanation:

Given that in the June 2007 issue, Consumer Reports also examined the relative merits of top-loading and front-loading washing machines, testing samples of several different brands of each type.

The difference in mean values test gave a p value of 0.32

Confidence level = 95%

Alpha = 1-0.95 = 0.05

Compare p with alpha, here p >alpha

Hence we accept null hypothesis that there is no difference in the means.

Confidence interval method also will yield the same result.  i.e. confidence interval for difference of means would definitely contain 0 at 95% conf level.

So answer is yes

3 0
2 years ago
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