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3 years ago

What is the area of the shaded region? 21 mm 24 mm 42 mm 48 mm Save and Exit

Mathematics

1 answer:

Harrizon [31]3 years ago

6 0

Answer:

It seems that you have missed to upload the shaded region for this problem. you are requested to please provide the shaded region so that we can help you with this problem

Step-by-step explanation:

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I need help with questions #7 and #8 plz

katen-ka-za [31]

Answer:

7. A = 40.8 deg; B = 60.6 deg; C = 78.6 deg

8. A = 20.7 deg; B = 127.2 deg; C = 32.1 deg

Step-by-step explanation:

Law of Cosines

$c^2 = a^2 + b^2 - 2ab \cos C$

You know the lengths of the sides, so you know a, b, and c. You can use the law of cosines to find C, the measure of angle C.

Then you can use the law of cosines again for each of the other angles. An easier way to solve for angles A and B is, after solving for C with the law of cosines, solve for either A or B with the law of sines and solve for the last angle by the fact that the sum of the measures of the angles of a triangle is 180 deg.

We use the law of cosines to find C.

$18^2 = 12^2 + 16^2 - 2(12)(16) \cos C$

$324 = 144 + 256 - 384 \cos C$

$-384 \cos C = -76$

$\cos C = 0.2$

$C = \cos^{-1} 0.2$

$C = 78.6^\circ$

Now we use the law of sines to find angle A.

Law of Sines

$\dfrac{a}{\sin A} = \dfrac{b}{\sin B} = \dfrac{c}{\sin C}$

We know c and C. We can solve for a.

$\dfrac{a}{\sin A} = \dfrac{c}{\sin C}$

$\dfrac{12}{\sin A} = \dfrac{18}{\sin 78.6^\circ}$

Cross multiply.

$18 \sin A = 12 \sin 78.6^\circ$

$\sin A = \dfrac{12 \sin 78.6^\circ}{18}$

$\sin A = 0.6535$

$A = \sin^{-1} 0.6535$

$A = 40.8^\circ$

To find B, we use

m<A + m<B + m<C = 180

40.8 + m<B + 78.6 = 180

m<B = 60.6 deg

I'll use the law of cosines 3 times here to solve for all the angles.

Law of Cosines

$a^2 = b^2 + c^2 - 2bc \cos A$

$b^2 = a^2 + c^2 - 2ac \cos B$

$c^2 = a^2 + b^2 - 2ab \cos C$

Find angle A:

$a^2 = b^2 + c^2 - 2bc \cos A$

$8^2 = 18^2 + 12^2 - 2(18)(12) \cos A$

$64 = 468 - 432 \cos A$

$\cos A = 0.9352$

$A = 20.7^\circ$

Find angle B:

$b^2 = a^2 + c^2 - 2ac \cos B$

$18^2 = 8^2 + 12^2 - 2(8)(12) \cos B$

$324 = 208 - 192 \cos A$

$\cos B = -0.6042$

$B = 127.2^\circ$

Find angle C:

$c^2 = a^2 + b^2 - 2ab \cos C$

$12^2 = 8^2 + 18^2 - 2(8)(18) \cos B$

$144 = 388 - 288 \cos A$

$\cos C = 0.8472$

$C = 32.1^\circ$

8 0

3 years ago

Bryan has a square parcel of land that is 120 yards long and 120 yards wide. The land is planted with Bermuda grass and surround

bagirrra123 [75]

Diagonal = s * sqrt 2.....with s(side) being 120 yds
diagonal = 120 * sqrt 2 = 169.7 yds rounds to 170 yds....or if u need it in feet, it is (3 * 170) = 510 ft.

7 0

3 years ago

Name the operation you should preform first

Colt1911 [192]

1. 4 times 6
2. 8 divided by 2
3. 4 squared 2

3 0

3 years ago

Read 2 more answers

Frank rode his bicycle for 4 miles on Saturday. How many yards did he ride his bicycle?

denis23 [38]

Answer:

7,040 yards

Step-by-step explanation:

there are 1,760 yards in a mile, so 1,760 multiplied by 4 is 7,040

7 0

3 years ago

Most major airlines allow passengers to carry two pieces of luggage (of a certain maximum size) onto the plane. However, their s

leonid [27]

Answer:

d) (179.20, 212.716)

Step-by-step explanation:

1000 : 345

569 : 195.96

Midpoint of (179.20, 212.716) is 195.958 which is the closest to 195.96

4 0

3 years ago