What is 2/11 as a decimal rounded to 3 decimal places?

Mathematics

1 answer:

Bad White [126]2 years ago

8 0

Answer: The answer is 0.182

Hope this help :)

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18.67% probability that the sample proportion does not exceed 0.1

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

For the sampling distribution of a sample proportion, we have that $\mu = p, \sigma = \sqrt{\frac{p(1-p)}{n}}$