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faltersainse [42]
2 years ago
6

Question 7 of 10 What is the length of BC in the right triangle below?

Mathematics
2 answers:
kramer2 years ago
8 0

Answer:

A

Step-by-step explanation:

horsena [70]2 years ago
7 0

Answer:

A

Step-by-step explanation:

Using Pythagoras' identity in the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

BC² = 9² + 12² = 81 + 144 = 225 ( take the square root of both sides )

BC = \sqrt{225} = 15 → A

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Sherry’s pay rate is $18.75 per hour; last week she worked 50 hours. Calculate her gross pay for the week.
saveliy_v [14]

Answer:

937.5

Step-by-step explanation:

$18.75 - 1 hour

$x. - 50hours

cross multiply the 18.75 with 50.

5 0
3 years ago
What is the answer for number 11. Please
Zolol [24]
#11
Each roll is 9' long, 
length of each roll = 9' * (12"/foot) = 108"
Each ribbon piece = 15", so number of ribbons per roll
=108/15=7 with 3" left over, which is assumed not possible to be joined with other pieces.
Therefore, with 5 rolls, there are 7*5=35 pieces of ribbon, with 5 pieces or 3" left over.
8 0
3 years ago
Write the standard form equation of the ellipse shown in the graph, and identify the foci.
vlada-n [284]

Answer option A

From the given graph is a Vertical ellipse

Center of ellipse = (-2,-3)

Vertices are (-2,3)  and (-2,-9)

Co vertices are (-6,-3) and (2,-3)

The distance between center and vertices = 6, so a= 6

The distance between center and covertices = 4 , so b= 4

The general equation of vertical ellipse is

\frac{(x-h)^2}{b^2} + \frac{(y-k)^2}{a^2}=1

(h,k) is the center

we know center is (-2,-3)

h= -2, k = -3 , a= 6  and b = 4

The standard equation  becomes

\frac{(x+2)^2}{4^2} + \frac{(y+3)^2}{6^2}=1

\frac{(x+2)^2}{16} + \frac{(y+3)^2}{36}=1

Foci  are (h,k+c)  and (h,k-c)

c=\sqrt{a^2-b^2}

Plug in the a=6  and b=4

c=\sqrt{6^2-4^2}

 c=\sqrt{20}

  c=2\sqrt{5}, we know h=-2  and k=-3

Foci  are   (-2,-3+2\sqrt{5})  and  (-2,-3-2\sqrt{5})

Option A is correct

6 0
3 years ago
What is the greatest common factor of 42,84,and 105 and how do you find it
klemol [59]
The GCF Of All Those Numbers Would Be 7.
6(7)= 42
12(7)= 84
15(7)= 105
7 0
3 years ago
Find the length of the hypotenuse of an isosceles right triangle whose legs are 1 unit in length.
Kobotan [32]
h =  \sqrt{ 1^{2} + 1^{2} } = \sqrt{1+1} = \sqrt{2}
7 0
3 years ago
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