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jek_recluse [69]
3 years ago
8

These are questions 2-5 out of 20. are these correct!?

Mathematics
1 answer:
dusya [7]3 years ago
3 0
I believe so, but It is kind of blurry for some reason on my screen but from what I can make out yes.
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Plz help me! Well put brainliest
Alex777 [14]
It is the last one since you must multiply all the sides to get volume.

Plz give brainliest
3 0
3 years ago
Read 2 more answers
What conditions must hold for a probability distribution to be acceptable?
VashaNatasha [74]

A distribution of probabilities is a numerical means of describing all unique combinations and the probabilities for a provided random variable, and the further discussion can be defined as follows:

  • The distributions mean (average), basic difference, skewness, as well as courtesies, are among such factors.
  • A formula, table, or chart can show a probability distribution for discrete probability distribution X that providing \bold{p(x) = P(X=x)} for all x.
  • For just a discrete random variable, the probability assigns annual probabilities with only a countless multitude of unique x values.
  • <em><u>Each result is likely to be between 0 and 1, including.</u></em>

Therefore, the final choice is "Option A".

Learn more:

brainly.com/question/15848153

3 0
3 years ago
Please help
alexandr402 [8]
\bf 3\sqrt[3]{2a} -6\sqrt[3]{2a}\qquad \stackrel{add ing~like-terms}{\implies }\qquad -3\sqrt[3]{2a}
3 0
3 years ago
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How do i find the perimeter?
Arada [10]

Answer: 8x+12

Step-by-step explanation:

perimeter equals (x+4) + (3x+2) + (x+4) + (3x+2) = x+4 + 3x+2 + x+4 + 3x+2 = 8x+12

8 0
3 years ago
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Write down the negation of each statement
prohojiy [21]

Answer:

1. ∀ y ∈ Z such that ∃ x ∈ Z, ¬R (x + y)

2. ∃ x ∈ Z, ∀ y ∈ Z such that ¬R(x + y)

Step-by-step explanation:

If we negate a quantified statement, first we negate all the quantifiers in the statement from left to right, ( keeping the same order ) then we negative the statement,

Here, the given statement,

1. ∃y ∈Z such that ∀x ∈Z, R (x + y)

By the above definition,

Negation of this statement is ∀ y ∈ Z such that ∃ x ∈ Z, ¬R (x + y),

2. Similarly,

The negation of statement ∀x ∈Z, ∃y∈Z such that R(x + y),

∃ x ∈ Z, ∀ y ∈ Z such that ¬R(x + y)

6 0
3 years ago
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