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vagabundo [1.1K]
3 years ago
6

A range of a set of numbers is 30. The highest number in the set is two times larger than the lowest number in the set. Which se

t of algebraic equations will solve for the highest and lowest numbers in the set?
Mathematics
1 answer:
Savatey [412]3 years ago
3 0
X = 2y
x-y = 30

x is the highest number and y is the lowest
Mark my answer brainliest please! Hope this helped!
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What is 1024 1/5 simplified?
frutty [35]
\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{  n}}}\implies \cfrac{1}{a^{-{{  n}}}}\\\\
-------------------------------\\\\
1024\frac{1}{5}\qquad 
\begin{cases}
1024=2^{10}\\
\frac{1}{5}=5^{-1}
\end{cases}\implies 2^{10}5^{-1}
6 0
2 years ago
Need help with this please
Katarina [22]

Answer:

The third side is sqrt(77)

Step-by-step explanation:

Since this is a right triangle we can use the Pythagorean theorem

a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse

2^2 + b^2 = 9^2

4+ b^2 = 81

Subtract 4 from each side

b^2 = 81-4

b^2=77

Take the square root of each side

sqrt(b^2) = sqrt(77)

b = sqrt(77)

The third side is sqrt(77)

5 0
3 years ago
Q: A is 8km due north of phone mast B. C is 9.5km due west of phone mast B. Calculate the distance AC
Evgen [1.6K]

Answer:

AC = 12.4 km (nearest tenth)

Step-by-step explanation:

AC can be calculated by using Pythagorean Theorem.

Thus:

AC² = AB² + BC²

Plug in the values

AC² = 8² + 9.5²

AC + √{154.25)

AC = 12.4 km (nearest tenth)

7 0
2 years ago
Scale copies.
Ksivusya [100]

Step-by-step explanation:

The value of x is 7......

8 0
3 years ago
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Write the equation for the following relation. Include all of your work in your final answer. Submit your solution.
ella [17]

Answer:

y=x^3

Step-by-step explanation:

The given relation is Q = {(x, y): (2, 8), (3, 27), (4, 64), (5, 125), . . .}

We can quickly recognize a pattern to write the equation of the given relation.

We can observe the following pattern among the x and y coordintaes.

8=2^3

27=3^3

64=4^3

125=5^3

We can see that the base of the powers on the right are the x-values of the relation and the values on the left are the y-values.

Hence, for any ordered pair (x,y), the equation is

y=x^3

5 0
3 years ago
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