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Rus_ich [418]
2 years ago
9

A car is traveling along a test track in the desert at a constant rate of 85 feet per second The test track has a length of 10,0

00 feet, and the track is marked by foot for observation purposes. After 8 seconds, the car is at foot marker 1000 feet. At what foot marker was the car at time t= 0 seconds?
Mathematics
1 answer:
jeyben [28]2 years ago
4 0

Answer:

foot marker 320 at t=0

Step-by-step explanation:

8 sec x 85 ft/s =680 ft

1,000ft - 680 ft = 320 ft

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6 0
3 years ago
In Juan's coin bank there are nickels (n),
alukav5142 [94]

Answer:

The answer is 8 quarters, 16 nickles, and 32 dimes

Step-by-step explanation:

  1. First, the equation would be (2/4d) x 5 +d x 10 +1/4d x 25= 600 (Don't put 6.00, that's dollars. We put 6 dollars into cents to make it easier.)
  2. Then we slowly start to solve: 10/4d + 10d + 25/4d = 600
  3. 10d+40d+25d/4 = 600 (Put all of that over 4, not first 25d)
  4. 75d= 600 x 4
  5. d=600 x 4/75 (same here put everything over 75)
  6. d=32
  7. So then n= 2 x 32/4 = 16
  8. Then n would be equal to : 1/4d= 1/4 x 32 = 8
  9. So your answer would be 8 quarters, 16 nickles, and 32 dimes.

Hope this helped :)

5 0
3 years ago
the perimeter of a rectangular plot of land whoose length is 2x+15and width x-10m is 80cm find the area of x​
Mnenie [13.5K]

Answer:

x=25

the area of x squared is then 625

Step-by-step explanation:

3x +5 = 80

3x= 75

x=25

the area of x squared is then 625

5 0
3 years ago
If perpendiculars from any point within an angle on its arms are equal, prove that it lies on the bisector of that angle
Oxana [17]
Your question can be quite confusing, but I think the gist of the question when paraphrased is: P<span>rove that the perpendiculars drawn from any point within the angle are equal if it lies on the angle bisector?

Please refer to the picture attached as a guide you through the steps of the proofs. First. construct any angle like </span>∠ABC. Next, construct an angle bisector. This is the line segment that starts from the vertex of an angle, and extends outwards such that it divides the angle into two equal parts. That would be line segment AD. Now, construct perpendicular line from the end of the angle bisector to the two other arms of the angle. This lines should form a right angle as denoted by the squares which means 90° angles. As you can see, you formed two triangles: ΔABD and ΔADC. They have congruent angles α and β as formed by the angle bisector. Then, the two right angles are also congruent. The common side AD is also congruent with respect to each of the triangles. Therefore, by Angle-Angle-Side or AAS postulate, the two triangles are congruent. That means that perpendiculars drawn from any point within the angle are equal when it lies on the angle bisector

4 0
3 years ago
What’s the equation of a line passing through the two points (-3,3) and (0,-1)
kirill [66]

Answer:

y = -4/3x - 1

Step-by-step explanation:

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