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Rus_ich [418]
3 years ago
9

A car is traveling along a test track in the desert at a constant rate of 85 feet per second The test track has a length of 10,0

00 feet, and the track is marked by foot for observation purposes. After 8 seconds, the car is at foot marker 1000 feet. At what foot marker was the car at time t= 0 seconds?
Mathematics
1 answer:
jeyben [28]3 years ago
4 0

Answer:

foot marker 320 at t=0

Step-by-step explanation:

8 sec x 85 ft/s =680 ft

1,000ft - 680 ft = 320 ft

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I don't understand how to solve this pls help
Charra [1.4K]

the sine function is a many-to-one function and therefore has no inverse function.

However if the domain is restricted to -90° ≤ x ≤ 90°

Then the function is one-to-one for this domain

Thus, sin^{-1} x is defined as the angle such that - π/2 ≤ x ≤ π/2

5π/6 is therefore outwith the domain



7 0
3 years ago
A helicopter leaves bristol and flies due east for 10 miles.Then the helicopter flies 8miles north before landing. What is the d
DedPeter [7]

Answer:

The distance of the helicopter from the bristol is approximately 1<u>2.81 miles</u>

Step-by-step explanation:

Given:

Helicopter flies 10 miles east of bristol.

Then the helicopter flies 8 miles North before landing.

To find the direct distance between the helicopter and bristol.

Solution:

In order to find the distance of the helicopter from the bristol before landing, we will trace the path of the helicopter

The helicopter is first heading 10 miles east of bristol and then going 8 miles due north.

On tracing the path of the helicopter we find that the direct distance of the helicopter from the bristol is the hypotenuse of a right triangle formed by enclosing the path of the helicopter.

Applying Pythagorean theorem to find the hypotenuse of the triangle.

Hypotenuse^2=Short\ leg^2+Shortest\ leg^2

Hypotenuse^2=10^2+8^2

Hypotenuse^2=100+64\\Hypotenuse^2=164

Taking square root both sides.

\sqrt{Hyptenuse^2}=\sqrt{164}\\Hypotenuse = 12.81\ miles

Thus, the distance of the helicopter from the bristol is approximately 12.81 miles

6 0
4 years ago
I WILL MARK BRAINLIEST FOR THIS!!!!!!!!!!!
igomit [66]

Answer:

She gets a job as a lawyer after graduation.

Step-by-step explanation:

6 0
2 years ago
Nazerhy deposits $8,000 in a certificate of deposit. The annual interest rate is 6%, and the interest will be compounded monthly
Likurg_2 [28]

Answer:

A=\$14,555.17

Step-by-step explanation:

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t=10\ years\\ P=\$8,000\\ r=6\%=6/100=0.06\\n=12  

substitute in the formula above

A=8,000(1+\frac{0.06}{12})^{12*10}  

A=8,000(1.005)^{120}  

A=\$14,555.17

4 0
4 years ago
QUESTION TWO Determine whether or not a constant function can be
Sveta_85 [38]
<h3>Answers:</h3>
  • (a) It is <u>never</u> one-to-one
  • (b) It is <u>never</u> onto

=========================================================

Explanation:

The graph of any constant function is a horizontal flat line. The output is the same regardless of whatever input you select. Recall that a one-to-one function must pass the horizontal line test. Horizontal lines themselves fail this test. So this is sufficient to show we don't have a one-to-one function here.

Put another way: Let f(x) be a constant function. Let's say its output is 5. So f(x) = 5 no matter what you pick for x. We can then show that f(a) = f(b) = 5 where a,b are different values. This criteria is enough to show that f(x) is not one-to-one. A one-to-one function must have f(a) = f(b) lead directly to a = b. We cannot have a,b as different values.

----------------------------

The term "onto" in math, specifically when it concerns functions, refers to the idea of the entire range being accessible. If the range is the set of all real numbers, then we consider the function be onto. There's a bit more nuance, but this is the general idea.

With constant functions, we can only reach one output value (in that example above, it was the output 5). We fall very short of the goal of reaching all real numbers in the range. Therefore, this constant function and any constant function can never be onto.

4 0
3 years ago
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