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Rus_ich [418]
2 years ago
9

A car is traveling along a test track in the desert at a constant rate of 85 feet per second The test track has a length of 10,0

00 feet, and the track is marked by foot for observation purposes. After 8 seconds, the car is at foot marker 1000 feet. At what foot marker was the car at time t= 0 seconds?
Mathematics
1 answer:
jeyben [28]2 years ago
4 0

Answer:

foot marker 320 at t=0

Step-by-step explanation:

8 sec x 85 ft/s =680 ft

1,000ft - 680 ft = 320 ft

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Solve for x and y <br> x+y=a<br> x−y=b <br> PLZ HELP VERY URGENT
antoniya [11.8K]

Answer:

Step-by-step explanation:

x+y=a

a=x+y

x−y=b

b=x−y

Good luck honey!

8 0
3 years ago
Brainly the polynomial x 3 + 5x 2 - ­57x -­ 4189 expresses the volume, in cubic inches, of a shipping box, and the width is (x+3
Simora [160]
Height would be 21 inches, depth would be 5. 
8 0
3 years ago
Help help help pls :)
kykrilka [37]

Answer:

opposite\approx 70.02

Step-by-step explanation:

The triangle in the given problem is a right triangle, as the tower forms a right angle with the ground. This means that one can use the right angle trigonometric ratios to solve this problem. The right angle trigonometric ratios are as follows;

sin(\theta)=\frac{opposite}{hypotenuse}\\\\cos(\theta)=\frac{adjacent}{hypotenuse}\\\\tan(\theta)=\frac{opposite}{adjacent}

Please note that the names (opposite) and (adjacent) are subjective and change depending on the angle one uses in the ratio. However the name (hypotenuse) refers to the side opposite the right angle, and thus it doesn't change depending on the reference angle.

In this problem, one is given an angle with the measure of (35) degrees, and the length of the side adjacent to this angle. One is asked to find the length of the side opposite the (35) degree angle. To achieve this, one can use the tangent (tan) ratio.

tan(\theta)=\frac{opposite}{adjacent}

Substitute,

tan(35)=\frac{opposite}{100}

Inverse operations,

tan(35)=\frac{opposite}{100}

100(tan(35))=opposite

Simplify,

100(tan(35))=opposite

70.02\approx opposite

4 0
2 years ago
If an object is dropped from a tower, then the velocity, V (in feet per second), of the object after t seconds can be obtained b
Amiraneli [1.4K]

Answer:

259.6 ft/sec

Step-by-step explanation:

it is a universal standard that acceleration due to gravity is 32ft/sec^2.

Now it can be verified by equation,

V(f) = V(i)+at (1st equation of motion derived by Newton's three laws of motion)

where,

V(f) is final velocity

V(i) is initial velocity

a is acceleration which is constant and have value 32ft/sec^2

t is time which is given as 7.8 seconds

In the given case, initial velocity that is V(i) will be 0ft/sec. Because, on dropping, object will start to move under the influence of gravity from zero speed.

So,

V(f) = 0 +(32) (7.8)

V(f) = 249.6 ft/sec

Now the condition is given that you have to add a constant 10 to the answer.

so, V(f) = 249.6 + 10

      V(f) = 259.6 ft/sec

5 0
3 years ago
Pls help need help ASAP 50 points you will be reported if the answer is wrong
aev [14]

Answer:

Part A = 10in = 35 ft

= 20 = 70 ft

Part B =

$ 178.5

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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