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koban [17]
2 years ago
10

Sodium has a density of 0.968 g/cm3 and crystallizes with a body-centered cubic unit cell. Part A Calculate the radius of a sodi

um atom.
Chemistry
1 answer:
Rudiy272 years ago
5 0

The radius of a sodium atom is determined as 2.145 x 10⁻⁸ cm.

<h3>What is body-centered cubic unit cell?</h3>

Body-centered cubic (BCC) is the name given to a type of atom arrangement found in nature.

A body-centered cubic unit cell structure consists of atoms arranged in a cube where each corner of the cube shares an atom and with one atom positioned at the center.

<h3>Volume of the sodium atom</h3>

The volume of the sodium atom is calculated as follows;

V = ZM/Nρ

where;

  • Z is 2 for  a body-centered cubic unit cell
  • M is mass of sodium atom = 23 g/mol
  • ρ is density of sodium atom
  • N is Avogadro's number

V = (2 x 23) / (6.023 x 10²³ x 0.968)

V = 7.89 x 10⁻²³ cm³

<h3>Edge length of the unit cell</h3>

a = (V)^¹/₃

a = (7.89 x 10⁻²³ cm³)^¹/₃

a = 4.29 x 10⁻⁸ cm

<h3>Radius of the unit cell</h3>

r = a/2

r = ( 4.29 x 10⁻⁸ cm) / 2

r = 2.145 x 10⁻⁸ cm

Thus, the radius of a sodium atom is determined as 2.145 x 10⁻⁸ cm.

Learn more about sodium atom here: brainly.com/question/25033306

#SPJ1

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