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vodomira [7]
3 years ago
5

Find the number of atoms in 237g Cu (molar mass of Cu63.55g/mol)

Chemistry
1 answer:
MakcuM [25]3 years ago
5 0
In order to find the amount of atoms you have to find the moles then multiply by Avogadro's Constant (L)

mol = \frac{MASS}{Molar Mass}
 
       = \frac{237 g}{63.55 g/mol}  

       
       =  3.73 mol

Number of atoms of Cu =  mol × L
                
                                      = 3.73 mol × (6.02 × 10²³)
                          
                                      = 2.245 × 10²⁴ atoms of copper


 
 


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Scientist who discovered the atomic nucleus is ________. dalton b. thomson chadwick d. rutherford
german
It’s D. Rutherford discovered the atomic nucleus.
7 0
3 years ago
What is the name of this hydrocarbon?
Cerrena [4.2K]

Answer:

C. 2-methylpropane

Explanation:

There are rules guiding the naming of hydrocarbons. Some of the rules are:

1.) The longest continuous chain is the parent chain:

The longest chain here is made up of 3-carbon atoms which is a propane compound

2.)The carbon atoms are numbered in the parent chain to indicate where branching or substitution takes place.

Here, it is in the second carbon atom in propane.

The branched group is methyl- which is a methane molecule that has lost a hydrogen atom.

This makes ths name of the compound to be:

2-methylpropane

6 0
3 years ago
write a balanced equation to determine the molarity of the HCI solution when a 24.6 ml sample of HCI reacts with a 33.0 mL of 0.
MatroZZZ [7]

Answer: 0.30 M

Explanation:

HCl+NaOH\rightarrow NaCl+H_2O

According to the neutralization law,

n_1M_1V_1=n_2M_2V_2

where,

M_1 = molarity of HCl solution = ?

V_1 = volume of HCl solution = 24.6 ml

M_2 = molarity of NaOH solution = 0.222 M

V_2 = volume of NaOH solution = 33.0 ml

n_1 = valency of HCl = 21

n_2 = valency of NaOH = 1

1\times M_1\times 24.6=1\times 0.222\times 33.0

M_1=0.30M

Therefore, the molarity of the HCI solution is 0.30 M

5 0
3 years ago
Read 2 more answers
Whith of the following numbers is biger than 9.20 x 10-7?​
avanturin [10]

Answer:

(9.20×10)-7

92-7

=85

Explanation:

Multiplication comes first in BODMAS

Hope it helps

5 0
3 years ago
How many moles are present 560.0 g of iron (lll) sulfate
xxMikexx [17]

Answer:

1.400 mol

Explanation:

To convert grams to moles, you will need the molar mass.  The molar mass of iron(iii) sulfate is 399.88 g/mol.  Divide grams by the molar mass to find moles.

(560.0 g)/(399.88 g/mol) = 1.400 mol

There are 1.400 mol present in 560.0 g of iron(iii) sulfate.

3 0
4 years ago
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