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serious [3.7K]
3 years ago
8

What is the measure of 27? 13 4 1370 A 330 B. 1370 430 D 470

Mathematics
1 answer:
finlep [7]3 years ago
4 0

Answer:

B. yes.

Step-by-step explanation:

dd_rrdrdy]uuhhhgffdddddddddddddddddddddd

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For what values of does the equation (2 + 1)^2 + 2 = 10 − 6 have two real and equal roots?
adelina 88 [10]

Answer:

(2 + 1)^2 + 2 = 10 - 6  

Falso

Step-by-step explanation:

The left side  

11

does not equal to the right side  

4

, which means that the given statement is false.

False

4 0
2 years ago
in a game if you roll a six on a six sided number cube you loose a turn. What is the probability you roll a 6
olga nikolaevna [1]
It would be 1/6 since there is only one six on a number cube
5 0
3 years ago
Read 2 more answers
Find the components of the vertical force Bold Upper Fequalsleft angle 0 comma negative 8 right anglein the directions parallel
nydimaria [60]

Answer with Step-by-step explanation:

We are given that

F=<0,-8>=0i-8j=-8j

\theta=\frac{\pi}{3}

The component of force is divided into two direction

1.Along the plane

2.Perpendicular to the plane

1.The vector parallel to the plane will be=r=cos\frac{\pi}{3}i-sin\frac{\pi}{3}j=\frac{1}{2}i-\frac{\sqrt 3}{2}j

By using cos\frac{\pi}{3}=\frac{1}{2},sin\frac{\pi}{3}=\frac{\sqrt 3}{2}

Force along the plane will be=\mid F_x\mid=F\cdot r

Force along the plane will be =\mid F_x\mid=F\cdot (\frac{1}{2}i-\frac{\sqrt 3}{2}j)=-8j\cdot(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=8\times \frac{\sqrt 3}{2}=4\sqrt 3N

By using i\cdot i=j\cdoty j=k\cdot k=1,i\cdot j=j\cdot k=k\cdot i=j\cdot i=k\cdot j=i\cdot k=0

Therefore, force along the plane=\mid F_x\mid(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=4\sqrt 3(\frac{1}{2}i-\frac{\sqrt 3}{2}j)

2.The vector perpendicular to the plane=r=-sin\frac{\pi}{3}-cos\frac{\pi}{3}=-\frac{\sqrt 3}{2}i-\frac{1}{2}j

The force perpendicular to the plane=\mid F_y\mid=F\cdot r=-8j(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)

The force perpendicular to the plane=4N

Therefore, F_y=4(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)

Sum of two component of force=F_x+F_y=4\sqrt 3(\frac{1}{2}i-\frac{\sqrt 3}{2}j)+4(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)

Sum of two component of force=2\sqrt 3i-6j-2\sqrt3 i-2j=-8j

Hence,sum of two component of forces=Total force.

6 0
3 years ago
Please someone help I’ll give u more points help quick!
Flura [38]
Can you give me more information about it please
7 0
2 years ago
Explain the error in the work shown. Find the correct answer.
svetlana [45]

The bases were not the same when the exponents were set equal to each other.

16 should have been written as 4 squared.

The exponent on the right should be 4a instead of 8a.

The correct solution is a=-3/4.

3 0
3 years ago
Read 2 more answers
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