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3 years ago

What is the measure of 27? 13 4 1370 A 330 B. 1370 430 D 470

Mathematics

1 answer:

finlep [7]3 years ago

4 0

Answer:

B. yes.

Step-by-step explanation:

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For what values of does the equation (2 + 1)^2 + 2 = 10 − 6 have two real and equal roots?

adelina 88 [10]

Answer:

(2 + 1)^2 + 2 = 10 - 6

Falso

Step-by-step explanation:

The left side

does not equal to the right side

, which means that the given statement is false.

False

4 0

2 years ago

in a game if you roll a six on a six sided number cube you loose a turn. What is the probability you roll a 6

olga nikolaevna [1]

It would be 1/6 since there is only one six on a number cube

5 0

3 years ago

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Find the components of the vertical force Bold Upper Fequalsleft angle 0 comma negative 8 right anglein the directions parallel

nydimaria [60]

Answer with Step-by-step explanation:

We are given that

F=<0,-8>=0i-8j=-8j

$\theta=\frac{\pi}{3}$

The component of force is divided into two direction

1.Along the plane

2.Perpendicular to the plane

1.The vector parallel to the plane will be= $r=cos\frac{\pi}{3}i-sin\frac{\pi}{3}j=\frac{1}{2}i-\frac{\sqrt 3}{2}j$

By using $cos\frac{\pi}{3}=\frac{1}{2},sin\frac{\pi}{3}=\frac{\sqrt 3}{2}$

Force along the plane will be= $\mid F_x\mid=F\cdot r$

Force along the plane will be = $\mid F_x\mid=F\cdot (\frac{1}{2}i-\frac{\sqrt 3}{2}j)=-8j\cdot(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=8\times \frac{\sqrt 3}{2}=4\sqrt 3$ N

By using $i\cdot i=j\cdoty j=k\cdot k=1,i\cdot j=j\cdot k=k\cdot i=j\cdot i=k\cdot j=i\cdot k=0$

Therefore, force along the plane= $\mid F_x\mid(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=4\sqrt 3(\frac{1}{2}i-\frac{\sqrt 3}{2}j)$

2.The vector perpendicular to the plane= $r=-sin\frac{\pi}{3}-cos\frac{\pi}{3}=-\frac{\sqrt 3}{2}i-\frac{1}{2}j$

The force perpendicular to the plane= $\mid F_y\mid=F\cdot r=-8j(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)$

The force perpendicular to the plane= $4$ N

Therefore, $F_y=4(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)$

Sum of two component of force= $F_x+F_y=4\sqrt 3(\frac{1}{2}i-\frac{\sqrt 3}{2}j)+4(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)$

Sum of two component of force= $2\sqrt 3i-6j-2\sqrt3 i-2j=-8j$

Hence,sum of two component of forces=Total force.

6 0

3 years ago

Please someone help I’ll give u more points help quick!

Flura [38]

Can you give me more information about it please

7 0

2 years ago

Explain the error in the work shown. Find the correct answer.

svetlana [45]

The bases were not the same when the exponents were set equal to each other.

16 should have been written as 4 squared.

The exponent on the right should be 4a instead of 8a.

The correct solution is a=-3/4.

3 0

3 years ago

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