Answer:
![\frac{1}{4}(\frac{2}{3}\times 0.8)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D%28%5Cfrac%7B2%7D%7B3%7D%5Ctimes%200.8%29)
Step-by-step explanation:
We are write a numerical expression for the given word phrase.
A fourth would be
.
The product of two-thirds and 0.8 would be
.
A fourth as much as the product of two-thirds and 0.8 would be ![\frac{1}{4}(\frac{2}{3}\times 0.8)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D%28%5Cfrac%7B2%7D%7B3%7D%5Ctimes%200.8%29)
Therefore, our required expression would be
.
Answer:
The answer is 0
Step-by-step explanation:
3n(3m-2n) + 6m^2= (6m-3n)(2n+m)
By expansion
9mn - 6n^2 + 6m^2 = 12mn + 6m^2 -6n^2 - 3mn
By collecting like terms
9mn - 12mn + 3mn - 6n^2 + 6n^2 + 6m^2 - 6 m^2 = 0
-3mn + 3mn=0
Therefore the simplification of the expansion gives us 0
Answer:
BAD = 64°
Step-by-step explanation:
ADE = (180-52):2 = 64°
ED || AB => ADE = BAD = 64°
I solved with addition elimination, and matrices elimination and received the same answer. (0,0,-3) I hope that helps.
Initial value is differential equation with a specific value given some point of the domain situation. Hope this helps!