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In-s [12.5K]
3 years ago
14

Solve this equation 3t-4(t-0)​

Mathematics
1 answer:
Gennadij [26K]3 years ago
6 0
The answer to that would be -1t
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Help im bad at math AHHHHHHHHHHHHHHHHHHHHH
ICE Princess25 [194]

Answer:

36

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Solve the Equation. 14x+28=14
Korvikt [17]

Answer:

x= -1

Step-by-step explanation:

1. First, you need to combine like terms. Constants with constants and variables with variables. Since there is only one variable, there is nothing to combine it with so nothing happens to it. The constants, on the other hand, can combine.

2. You have to subtract 28 from 28 and 14 so that +28 can cancel out on the left side and combine on the right.

3. That will leave you with 14x= -14.

4. Now you need to get x on its own so you need to divide 14 (opposite of multiplication to cancel out) on both sides.

5. That will leave you with x= -1. That is your final answer.

Hope this helps! Please vote me as Brainliest. Let me know if you need more of an explanation. Remember, cheating is never the answer. Try your best before you seek answers. Hope it's not too late. Good luck with whatever you are doing! Have an amazing day!

8 0
3 years ago
Which other expression has the same value as (-14) - (-8) ?
harina [27]

Answer:

The first answer choice, (-14) + 8

Step-by-step explanation:

1. Solve (-14) - (-8)

(-14) - (-8) = -6

2. Solve the answer choices

(-14) + 8= -6

14 - (-8)= 22

14 + (-8)= 6

(-14) + (-8)= -22

7 0
3 years ago
Pls pls pls help if ur good with angles and sides ​
liq [111]

Answer:

∆PQR: Equilateral Triangle

∆PRT: Scalene Triangle

∆TQS: Isosceles Triangle

∆QNP: Right Triangle

Step-by-step explanation:

∆PQR is an Equilateral Triangle because all of its angles are equal (60°).

∆PRT is a Scalene Triangle because none of its sides are equal.

The triangle above it is equilateral, and one side length is 14, meaning all of its side lengths are 14.

This makes the top of ∆PRT 14. The hypotenuse is given and it’s 18.

The last side left is clearly shorter than both, meaning none of the sides are equal.

∆TQS is an Isosceles Triangle because 2 angles are equal.

The base angles are both 76°.

∆QNP is a Right Triangle because segment QN and PR are perpendicular, creating two 90° angles on both sides.

For number 10, I suggest using a graphing calculator or desmos to graph the points. (Or you can just add the points but I suggest graphing).

From there, you can count the length of each side.

Segment DE: 9

Segment EF: 8

Segment FD: 10

This makes ∆DEF in number 10 a Scalene Triangle because none of its sides are equal.

For number 11, I also suggest graphing the points and counting the sides.

Segment DE: 7

Segment EF: 9

Segment FD: 7

This makes ∆DEF in number 11 an Isosceles Triangle because 2 of its sides are equal.

Hope this helps! :)

4 0
3 years ago
How to solve<br> 3/5e-6=-2/5(e-10)-7
kaheart [24]
\frac{3}{5} e-6=- \frac{2}{5}(e-10)-7
\frac{3}{5} e-6=- \frac{2}{5} e- \frac{2}{5}*(-10) -7 \\  \frac{3}{5} e-6=- \frac{2}{5} e+ \frac{20}{5} -7= \frac{3}{5} e-6=- \frac{2}{5} e+4 -7= \\
\frac{3}{5}e-6=- \frac{2}{5} e-3      /*5
3e-18=-2e-15        /+15
3e-3=-2e            /+2e
5e-3=0              /+3
5e=3
e=\frac{3}{5}
6 0
3 years ago
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