Answer:
cylinder has greatest volume
Step-by-step explanation:
solution
given,
radius of cylinder(r)=6cm
height of cylinder (h)=6cm
we know,
volume of cylinder=πr^2h
=22÷7×6×6×6
=4752÷7
=678.857cm^3
radius of cone(r)=6cm
height of cone(h)=12cm
we know,
volume of cone=1÷3πr^3
= 1÷3×22÷7×6×6×6
= 4752÷21
=226.2857cm^3
as a result,cylinder has greatest volume
Answer:
.
Step-by-step explanation:
All coterminal angles of an angle
are defined as
or 
where, n is an integer.
The given angle is

So, all coterminal angles of an angle
are

For n=1,




Since,
between 0 and 2π, therefore, the required coterminal angle is
.
Answer:
x=3
Step-by-step explanation:
x^2=9
x=3
4
Step by step explanation
Answer:
- <u>3 </u><u>and</u><u> 17</u> are required integers
Step-by-step explanation:
- Let one integer be x
- And other integer be y
x = 4y + 5
xy = 51
<u>According to </u><u>question </u><u>:</u>
➞ (4y + 5)y = 51
➞ 4y² + 5y = 51
➞ 4y² + 5y - 51 = 0
➞ 4y² + 17y - 12y - 51 = 0
➞ y (4y + 17) - 3(4y + 17) = 0
➞ (y - 3)(4y - 17) = 0
➞ y - 3 = 0
➞ <u>y = 3</u>
Hence,
➞ <u>y = 3</u>
➞ x = 4y + 5
➞ x = 4 (3) + 5
➞ x = 12 + 5
➞<u> </u><u>x = 17</u>
∴ The required integers are <u>3 and 17</u>