Answer:
Step-by-step explanation:
Initial Quantity of salt Q(0) = 100 kg
Capacity of tank = 1000 L
Inflow of liquid = 10 l /minute and outflow = same rate thus leaving the content of volume 1000 L at any time
Assume after entering constantly mixes and drains out.
Concentration flow = inflow - outflow
= 0.05(10) - 
i.e. 
, Q(0) = 100
Use Q(0) = 5
-45 = A
So the equation would be
a) Initial concentratin = 
b) Use the solution fo rDE substitute t =1
Q(1) = 50-45e^(-0.01) = 5.4477 kg
c) As t becomes large Q = 50
So concentration limit = 50/1000 = 0.05
Answer: 25, 31 and 37
Step-by-step explanation:
(2n-1)= 19, 21, 23, 25, 27, 29, 31, 33, 35, 37
(3n+1)= 19, 22, 25, 28, 31, 34, 37,
Answer:
x²+12x+27
Step-by-step explanation:
put the intercepts in intercept form which is a(x-p)(x-q)
That would be (x-3)(x-9)
Foil x²-9x-3x+27
Solve x²-12x+27
Answer:
Mai was moving faster.
As, she covered a greater distance in the same amount of time.
Step-by-step explanation:
Given: Mai traveled 15 meters in 6 seconds and Priya travels 22 meters in 10 second.
Calculate the speed of both;
Speed defined as the rate at which an object covers distance.
Mai traveled 15 meters in 6 seconds
then;
Speed = 
Priya travels 22 meters in 10 second.
then;
Speed = 
Reason: Mai traveled faster because she covered a greater distance in the same amount of time.
