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KATRIN_1 [288]
3 years ago
14

Write an algebraic expression with two terms to represent the total of balloons sold my all 3. in terms C

Mathematics
1 answer:
Karolina [17]3 years ago
6 0

Answer:

30/c

Step-by-step explanation:

Evaluate 7a+b/b+c, if a=2, b=6, and c=4.Find the solution of 3(y+7)is less than or equal to 39 if the replacement set is {2,4,6,8,10.12}. The equation 4+9=4+9 is an example of which property of equality?

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Find the area of the hexagon.<br> A) 36 in2 <br> B) 52 in2 <br> C) 78 in2 <br> D) 144 in2
s2008m [1.1K]

Answer: C) 78 in2

Step-by-step explanation:

The polygon is divided into two trapezoids with equal measurements.

Area of a trapezoid:

1

2

(b1 + b2)h

Since the area of the hexagon equals the area of two trapezoids with equal measurements, do not multiply by 1/2.

(b1 + b2)h

(10 + 16)3

26(3)

78 in2

4 0
3 years ago
I don’t know what to do here
Rudik [331]
The answer is CD = √3

This is because of the fact that a 30-60-90 right triangle has proportions of 1-√3-2 based on the length opposite of the angle. Since we are given the segment opposite to the right angle as 2, we know that we can use the base numbers for the proportions to find the rest. Since CD is opposite of the 60 degree angle, it must be √3.
5 0
4 years ago
Read 2 more answers
The amount $180.00 is what percent greater than $135.00
MrMuchimi

It is 33.33 Percent greater than $135.00

5 0
3 years ago
Read 2 more answers
Find the form of the general solution of y^(4)(x) - n^2y''(x)=g(x)
Dennis_Churaev [7]

The differential equation

y^{(4)}-n^2y'' = g(x)

has characteristic equation

<em>r</em> ⁴ - <em>n </em>² <em>r</em> ² = <em>r</em> ² (<em>r</em> ² - <em>n </em>²) = <em>r</em> ² (<em>r</em> - <em>n</em>) (<em>r</em> + <em>n</em>) = 0

with roots <em>r</em> = 0 (multiplicity 2), <em>r</em> = -1, and <em>r</em> = 1, so the characteristic solution is

y_c=C_1+C_2x+C_3e^{-nx}+C_4e^{nx}

For the non-homogeneous equation, reduce the order by substituting <em>u(x)</em> = <em>y''(x)</em>, so that <em>u''(x)</em> is the 4th derivative of <em>y</em>, and

u''-n^2u = g(x)

Solve for <em>u</em> by using the method of variation of parameters. Note that the characteristic equation now only admits the two exponential solutions found earlier; I denote them by <em>u₁ </em>and <em>u₂</em>. Now we look for a particular solution of the form

u_p = u_1z_1 + u_2z_2

where

\displaystyle z_1(x) = -\int\frac{u_2(x)g(x)}{W(u_1(x),u_2(x))}\,\mathrm dx

\displaystyle z_2(x) = \int\frac{u_1(x)g(x)}{W(u_1(x),u_2(x))}\,\mathrm dx

where <em>W</em> (<em>u₁</em>, <em>u₂</em>) is the Wronskian of <em>u₁ </em>and <em>u₂</em>. We have

W(u_1(x),u_2(x)) = \begin{vmatrix}e^{-nx}&e^{nx}\\-ne^{-nx}&ne^{nx}\end{vmatrix} = 2n

and so

\displaystyle z_1(x) = -\frac1{2n}\int e^{nx}g(x)\,\mathrm dx

\displaystyle z_2(x) = \frac1{2n}\int e^{-nx}g(x)\,\mathrm dx

So we have

\displaystyle u_p = -\frac1{2n}e^{-nx}\int_0^x e^{n\xi}g(\xi)\,\mathrm d\xi + \frac1{2n}e^{nx}\int_0^xe^{-n\xi}g(\xi)\,\mathrm d\xi

and hence

u(x)=C_1e^{-nx}+C_2e^{nx}+u_p(x)

Finally, integrate both sides twice to solve for <em>y</em> :

\displaystyle y(x)=C_1+C_2x+C_3e^{-nx}+C_4e^{nx}+\int_0^x\int_0^\omega u_p(\xi)\,\mathrm d\xi\,\mathrm d\omega

7 0
3 years ago
Can u help me I'm stuck
Hoochie [10]
All you have to do is multiply 3 with 25 to get 75 (:
4 0
3 years ago
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