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kenny6666 [7]
3 years ago
9

Please help me please

Mathematics
1 answer:
tankabanditka [31]3 years ago
4 0

Answer:

2,8

3,6

3,8

4,4

4,6

4,8

37.5% or 6/16

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How does the volume of an oblique cylinder change if the radius is reduced to 2/9 of its original size and the height is quadrup
Novay_Z [31]
New volume is given by:
New volume=(old volume)×(4×2/9×2/9)
simplifying the above we get:
New volume=(old volume)×16/81
Thus the new volume is 16/81 times the old volume
old volume=πr²h
Hence:
Answer:16/81πr²h


4 0
3 years ago
Is the number -<img src="https://tex.z-dn.net/?f=%5Cfrac%7B13%7D%7B1%7D" id="TexFormula1" title="\frac{13}{1}" alt="\frac{13}{1}
Alenkasestr [34]

Answer:

13/1 = 13 is the only number integer that divides into it, but all numbers that can be fractions are rational numbers, whether decimal or prime they all can be rational.

Step-by-step explanation:

4 0
3 years ago
The length of a rectangle is increasing at a rate of 6 cm/s and its width is increasing at a rate of 5 cm/s. When
atroni [7]

Answer:

The area of the rectangle is increasing at a rate of 84 square centimeters per second.

Step-by-step explanation:

The area for a rectangle is given by the formula:

A=w\ell

Where <em>w</em> is the width and <em>l</em> is the length.

We are given that the length of the rectangle is increasing at a rate of 6 cm/s and that the width is increasing at a rate of 5 cm/s. In other words, dl/dt = 6 and dw/dt = 5.

First, differentiate the equation with respect to <em>t</em>, where <em>w</em> and <em>l</em> are both functions of <em>t: </em>

\displaystyle \frac{dA}{dt}=\frac{d}{dt}\left[w\ell]

By the Product Rule:

\displaystyle \frac{dA}{dt}=\frac{dw}{dt}\ell +\frac{d\ell}{dt}w

Since we know that dl/dt = 6 and that dw/dt = 5:

\displaystyle \frac{dA}{dt}=5\ell + 6w

We want to find the rate at which the area is increasing when the length is 12 cm and the width is 4 cm. Substitute:

\displaystyle \frac{dA}{dt}=5(12)+6(4)=84\text{ cm}^2\text{/s}

The area of the rectangle is increasing at a rate of 84 square centimeters per second.

8 0
3 years ago
The table shows the cost of several bunches of bananas.
Alja [10]

Answer:

c=0.42 pounds

Step-by-step explanation:

You divide one of cost by the pounds to get how much one costs then you plug in the equation Cost= # of pound times 48

6 0
3 years ago
Read 2 more answers
The temperature in frostville was at 50*F at midnight,and it dropped at a constant rate for the next 10 hours.
bazaltina [42]

After 10 hours the temperature is shown on the graph as 30 degrees.

50 degrees - 30 degrees = 20 degrees.

The temperature dropped 20 degrees in 10 hours.

Divide the change by the time:

20 degrees / 10 hours = 2 degrees per hour.

Because the temperature dropped, the change would be negative.

The answer is D. -2 degrees per hour.

5 0
3 years ago
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