In the following: i. Find the zeros of each function

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Burka [1]

Answer:

there are 10

Step-by-step explanation:

10

4 0

3 years ago

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The square abcd has side length 10cm. E is the midpoint of BC. Work out the length of DE. Answer to 1 decimal place.

Levart [38]

-- DEC is a right triangle.

-- DC is one side of the square = 10 cm
-- EC is half the side of the square = 5 cm
-- DE is the hypotenuse = square root of (5² + 10²) = √(125 cm²) .

-- Truncated to one decimal place, that's 11.1 cm.

-- Rounded to one decimal place, it's 11.2 cm.

4 0

3 years ago

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Square Roots

dlinn [17]

4 is the square root of 16

i think that what you are asking, but if it is not tell me and i can try to help more :)

4 0

3 years ago

Suppose that in a random selection of 100 colored candies, 24% of them are blue. The candy company claims that the percentage

LuckyWell [14K]

Answer:

We conclude that the percentage of blue candies is equal to 23% at 0.01 significance level.

Step-by-step explanation:

We are given that in a random selection of 100 colored candies, 24% of them are blue.

The candy company claims that the percentage of blue candies is equal to 23%.

Let p = percentage of blue candies.

So, Null Hypothesis, $H_0$ : p = 23% {means that the percentage of blue candies is equal to 23%}

Alternate Hypothesis, $H_A$ : p $\neq$ 23% {means that the percentage of blue candies is different from 23%}

The test statistics that would be used here One-sample z proportion test statistics;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n}} }$ ~ N(0,1)

where, $\hat p$ = sample proportion of blue colored candies = 24%

n = sample of colored candies = 100

So, test statistics = $\frac{0.24-0.23}{\sqrt{\frac{0.24(1-0.24)}{100}} }$

= 0.234

The value of z test statistics is 0.234.

Now, at 0.01 significance level the z table gives critical values of -2.5758 and 2.5758 for two-tailed test.

Since our test statistics lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the percentage of blue candies is equal to 23%.

6 0

3 years ago

Consider the following portion of an electric circuit with three relays. Current will flow from point a to point b if there is a

Svetradugi [14.3K]

Answer:

0.9009

Step-by-step explanation:

Let X be the event that Current will flow

Let Y be the event that the first relay which is 1 is closed

Thus, we can say that every element of Y is in X, but X possesses more elements. Thus, Y ⊂ X.

Thus, we can say that;

P(X ∩ Y) = P(Y)

Thus, given that current flowed, the probability that relay 1 functioned will be expressed as;

P(Y | X) = (P(Y ∩ X))/P(X)

From earlier, we saw that P(X ∩ Y) = P(Y). Thus;

P(Y | X) = P(Y)/P(X)

From the question, P(Y) = 0.9

Since there are 3 relays, then we have;

P(X) = 1 - 0.1³ = 0.999

Thus;

P(Y | X) = 0.9/0.999

P(Y | X) = 0.9009

4 0

3 years ago