Answer:
42.6cm
Step-by-step explanation:
The sum total of all the sides of the shape is the perimeter of the shape. Hence;
Perimeter = x+3 + 4 + x+9 + 2x+5
Perimeter = 4x + 21
Given
Area of the figure = 75cm^2
Area = (x+3)(2x+5) + (2x+1)(6)
75 = 2x²+5x+6x+15+12x+6
75 = 2x²+23x+21
2x²+23x+21-75 = 0
2x²+23x-54 = 0
x = -23±√23²-4(2)(-75)/4
x = -23±√529+600/4
x = -12±√1129/4
x = -12+33.6/4
x = 21.6/4
x = 5.4
Recall that;
Perimeter = 4x+21
Perimeter = 4(5.4) + 21
Perimeter = 21.6+21
Perimeter = 42.6cm
Hence the perimeter is 42.6cm
Step-by-step explanation:
7+2x-2 = 4x -3
5= 2x -3
2x = 8
x = 4
Answer:
-4
Step-by-step explanation:
Answer:
Step-by-step explanation:
From the given information:
The uniform distribution can be represented by:
The function of the insurance is:
Hence, the variance of the insurance can also be an account forum.
![Var [I_{(x}) = E [I^2(x)] - [E(I(x)]^2](https://tex.z-dn.net/?f=Var%20%5BI_%7B%28x%7D%29%20%3D%20E%20%5BI%5E2%28x%29%5D%20-%20%5BE%28I%28x%29%5D%5E2)
here;
![E[I(x)] = \int f_x(x) I (x) \ sx](https://tex.z-dn.net/?f=E%5BI%28x%29%5D%20%3D%20%5Cint%20f_x%28x%29%20I%20%28x%29%20%5C%20sx)
![E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250) \ dx](https://tex.z-dn.net/?f=E%5BI%28x%29%5D%20%3D%20%5Cdfrac%7B1%7D%7B1500%7D%20%5Cint%20%5E%7B1500%7D_%7B250%7B%20%28x-%20250%29%20%5C%20dx)
Similarly;
![E[I^2(x)] = \int f_x(x) I^2 (x) \ sx](https://tex.z-dn.net/?f=E%5BI%5E2%28x%29%5D%20%3D%20%5Cint%20f_x%28x%29%20I%5E2%20%28x%29%20%5C%20sx)
![E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250)^2 \ dx](https://tex.z-dn.net/?f=E%5BI%28x%29%5D%20%3D%20%5Cdfrac%7B1%7D%7B1500%7D%20%5Cint%20%5E%7B1500%7D_%7B250%7B%20%28x-%20250%29%5E2%20%5C%20dx)
∴
![Var {I(x)} = 1250^2 \Big [ \dfrac{5}{18} - \dfrac{25}{144}]](https://tex.z-dn.net/?f=Var%20%7BI%28x%29%7D%20%3D%201250%5E2%20%5CBig%20%5B%20%5Cdfrac%7B5%7D%7B18%7D%20-%20%5Cdfrac%7B25%7D%7B144%7D%5D)
Finally, the standard deviation of the insurance payment is:
≅ 404
Some things you need to know:
1) You need to know how to convert standard form to slope y-int. form and slope y-int. form to standard form.
2) When two lines are parallel, the slopes are the same.
3) When two lines are perpendicular, the slopes are negative reciprocals of each other. (Or their product is -1)
example: 3/4 --> -4/3.
3/4 * -4/3 = -12/12 = -1
4) To find the value of b, substitute the point into the equation.
5) Convert the equation to slope y-int. form to find the slope.
6) When a line has an undefined slope, the slope y-int. will look either like
y = __ (forms horizontal line) or x = __ (forms vertical line).
To find the perpendicular of these lines, turn y to x / x to y.
To find the value of __, look at the point located in the line, so if x = ___
passes through (5,3), then x = 5 because x = 5 in the point. So the
equation would be x = 5.
Use online practice tests and other sources if you don't understand.
