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AysviL [449]
2 years ago
13

Find the value of the missing piece!! :)

Mathematics
1 answer:
dezoksy [38]2 years ago
7 0
I think it should be 42 but i might be wrong..
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Which term would be combined with the constant +2 in the expression -8x^2 + 3x + 2?
Naddik [55]

The answer to this question is NONE OF THE ABOVE



you would take each answer and add 2 to the end of it, then factor

8 0
3 years ago
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A plumber uses the expression 48 + 25h to determine the number of dollars to change each customer. If H = 4 how much does the cu
Oliga [24]

If H = 4, we simply plug 4 into the position of h in the expression.

48 + 25 * 4

48 + 100

148

The customer pays $148

5 0
3 years ago
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-2x + y = 5 <br><br> what does y equal and how did you solve it?
Olin [163]

Answer:

y=2x+5

Step-by-step explanation:

Let's solve for y.

−2x+y=5

Step 1: Add 2x to both sides.

−2x+y+2x=5+2x

y=2x+5

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3 years ago
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The Johnson twins were born eleven years after their older sister. This​ year, the product of the three​ siblings' ages is exact
vodka [1.7K]
So there are 3 siblings: the first twin, the second twin, and their older sister.

Since the sister is older by 11 years, you can represent their relationship with the following equation;
age of twin = age of older sister - 11
t = s - 11

Representing this next part may be a little hard to show, but i'll do my best :)

Adding the ages together can be represented like this;
total age = t + t + s
If the product of their ages ( t * t * s ) is 1181 more than the sum, you can show it like this:
t * t * s = (t + t + s) + 1181
Now you substitute in (s - 11) for t because s = t - 11.
t * t * s = (t + t + s) + 1181\\&#10;(s-11) * (s-11) * s = ((s-11) + (s-11) + s) + 1181\\&#10;(s^{2}-22x+121)*s=s+s-11-11+1181\\&#10;s^{3}-22s^{2}+121s-2s=1159\\&#10;s^{3}-22s^{2}+118s-1159=0
Factor:
Since it's a third-degree equation, I just entered it into a polynomial solver in my calculator. There was only one factor listed, x = 19. Using (s - 19) = 0 as a factor, the equation becomes the following:
s^{3}-22s^{2}+118s-1159=0\\&#10;(s-19)(s^{2}-3s+61)=0
Using the quadratic formula, you get:
s= \frac{-b(+-)\sqrt{b^{2}-4ac}}{2a}\\&#10;s= \frac{-(-3)(+-)\sqrt{(-3)^{2}-4(1)(61)}}{2*1}\\&#10;s= \frac{3(+-)\sqrt{(9)-244}}{2}\\&#10;s= \frac{3(+-)\sqrt{-235}}{2}

Since you have a square root of a negative number, the answer will be imaginary. You cannot have an age that is imaginary, so the age of the older sister (s) is 19 years.

Because t = s - 11, that means that t = (19) - 11 = 8.
t is the age of the twins, so the twins are 8 years old.
8 0
3 years ago
The nth term of the sequence <br> -2,1,4,7,10
alex41 [277]

Answer:

Step-by-step explanation:

An = -2+(n-1)3

An=-5+3n

8 0
3 years ago
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