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sukhopar [10]
3 years ago
8

I need help with these 2 algebra questions​

Mathematics
2 answers:
omeli [17]3 years ago
8 0

Answer:

question.4.

answer . b

question. 5

answer . 7m and -2m

Romashka-Z-Leto [24]3 years ago
3 0

Answer:

Step-by-step explanation:

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-2x + 5 (1 -7x ) =190
luda_lava [24]
The answer is x= -5 ...explained... -2x + 5 -35x= 190...-37x +5 = 190 ... now subtract 190-5 = 185... divide 185 by - 37 and get -5
8 0
3 years ago
Two parallel lines are _____ coplanar.
dimulka [17.4K]

Answer:

1. always

2. sometimes

Step-by-step explanation:

Two lines are coplanar if they lie in the same plane or in parallel planes. There is  ALWAYS a plane which contains two parallel lines (see first attached image for details).

Two lines that lie in parallel planes are sometimes parallel. For example, see at second image. Planes \alpha and \beta are parallel. Consider pair of lines a and a_1 - they are parallel, but if you consider the pair of lines a and b_1, you can see they are not parallel.

8 0
3 years ago
Read 2 more answers
5^(-x)+7=2x+4 This was on plato
Setler79 [48]

Answer:

Below

I hope its not too complicated

x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}

Step-by-step explanation:

5^{\left(-x\right)}+7=2x+4\\\\\mathrm{Prepare}\:5^{\left(-x\right)}+7=2x+4\:\mathrm{for\:Lambert\:form}:\quad 1=\left(2x-3\right)e^{\ln \left(5\right)x}\\\\\mathrm{Rewrite\:the\:equation\:with\:}\\\left(x-\frac{3}{2}\right)\ln \left(5\right)=u\mathrm{\:and\:}x=\frac{u}{\ln \left(5\right)}+\frac{3}{2}\\\\1=\left(2\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)-3\right)e^{\ln \left(5\right)\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)}

Simplify\\\\\mathrm{Rewrite}\:1=\frac{2e^{u+\frac{3}{2}\ln \left(5\right)}u}{\ln \left(5\right)}\:\\\\\mathrm{in\:Lambert\:form}:\quad \frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}

\mathrm{Solve\:}\:\frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}:\quad u=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)\\\\\mathrm{Substitute\:back}\:u=\left(x-\frac{3}{2}\right)\ln \left(5\right),\:\mathrm{solve\:for}\:x

\mathrm{Solve\:}\:\left(x-\frac{3}{2}\right)\ln \left(5\right)=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right):\\\quad x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}

3 0
3 years ago
Please help, will give brainliest! :)
Nonamiya [84]

Answer:

the answer is 2>am sorry if wrong

6 0
2 years ago
Can anyone help me out ?
AnnZ [28]

no se pero de seguro alguien más te ayudará

8 0
3 years ago
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