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2 years ago

9

Question 4 A B C D PLEASE HELP!!!

1 answer:

Savatey [412]2 years ago

5 0

Answer:

B

Step-by-step explanation:

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The circumference of a circle is 15ft. What is the length of the radius? Use 3.14 for pi. Round your answer to the nearest tenth

dybincka [34]

The circumference of the circle is determined by using the equation, C = 2πr. From this, the value of r may be solved by rearranging the equation to, r = C/2π. Substituting the given values,
r = 15 ft / (2 x 3.14)
The value of r is 2.3885 ft. Thus, the answer to the question is 2.4 ft.

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3 years ago

If g(x)= 4, then g(5x) = ?

Neporo4naja [7]

Answer:

g(5x)= 20

Step-by-step explanation:

g(x)=4 is basically saying that 1 x is equal to 4.

g(5x) wants to know what 5 times 1 x is equal to (5 times 4 (4 is equal to 1 x)

g(5x)= 5(x=4)

g(5x)= 20

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3 years ago

Find the absolute maximum and minimum values of f(x,y)=xy−4x in the region bounded by the x-axis and the parabola y=16−x2.

skad [1K]

Answer:

The absolute maximum and minimum is $20\; \text{and} -20.$

Step-by-step explanation:

We first check the critical points on the interior of the domain using the

first derivative test.

$f_x=y-4=0$

$f_y=x=0$

The only solution to this system of equations is the point (0, 4), which lies in the domain.

$f_{xx}=0, \;f_{yy}=0\; \text{and}\; f_{xy}=-1$

$\Rightarrow f_{xx}f_{yy}-f_{xy}=o-1=-1$

$\therefore (0,4)$ is a saddle point.

Boundary points - $(4,0), (-4,0), (0,16)$

Along boundary $y=16-x^2$

$f=x(16-x^2)-4x$

$=16x-x^3-4x$

$\Rightarrow f^'=16-3x^2-4=0$

$\Rightarrow 3x^2=12$

$\Rightarrow x=\pm2,\;\;y=14$

Values of f(x) at these points.

$\begin{array}{}(4,0)=-16\\(-4,0)=16\\(0,16)=0\\(2,14)=20\\(-2,14)=-20\end{array}$

Therefore, the absolute maximum and minimum is $20\; \text{and} -20.$

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3 years ago

ANSWER ALL THREE I WILL MAKE YOU THE BRAINLIEST EASY QUESTION

Anna35 [415]

Number 1 is 14/10 number 4 is 3 1/7 number 5 is 3 5/6

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3 years ago

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