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masha68 [24]
3 years ago
8

In square ABCD, diagonal DB is drawn. If the m

Mathematics
1 answer:
pshichka [43]3 years ago
6 0

9514 1404 393

Answer:

  x = 11

Step-by-step explanation:

The diagonal creates two isosceles right triangles, so ...

  m∠CBD = 45°

  3x +12 = 45

  3x = 33 . . . . . . subtract 12

  x = 11 . . . . . . . . divide by 3

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Can someone help me with my algebra homework I have 30 minutes until it's due 6 questions my insta is bahdanz
posledela

Answer:

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7 0
2 years ago
The midpoint of (3 x, -2) and (-4, 5y) is (1,4). find x, -y​
Mariana [72]

Answer:

(x,-y): (2,-2)

Step-by-step explanation:

M=(x+x)/2,(y+y)/2

Given (1,4)=

\frac{3x - 4}{2}

This implies:

1 =  \frac{3x - 4}{2}

3x - 4 = 2 \\ 3x = 2 + 4 \\  \frac{3x }{3}  =  \frac{6}{3}  \\ x = 2

In a similar way,

4 =  \frac{ - 2 + 5y}{2}  \\  - 2 + 5y = 8 \\ 5y = 10 \\ y = 2

The question demanded (x,-y)

Hence(2,-2) is the answer

7 0
2 years ago
Can someone give the answers for 1-6 ?
FromTheMoon [43]

Answer:

Step-by-step explanation:

1)3.14.16

2)78.54

3)12.57

4)346.36

5)72.38

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6 0
3 years ago
Solve the system by substitution.<br> y=6x<br> y=3x+21<br> ( , )
Dimas [21]

Answer:

(7,42)

Step-by-step explanation:

Imput the 6x for the Y:

6x=3x+21

move the variable to the left

6x-3x=21

collect like terms:

3x=21

divide both sides by 3x and youll get this for X

x=7

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6 0
3 years ago
Help me please Only no.2 no.3 no.8 no.6 no.9 and no.10
Reil [10]

Answer:

2) x³ (x² + 1) (x + 1)

3) (x - 6) (x + 6)

6)  (x + 3) (x - 4)

8) (5x + 3) (x - 2)

Step-by-step explanation:

I'm providing the solutions for numbers 2, 3, 6, and 8, in order to give you the opportunity to apply and practice the techniques demonstrated here for numbers 9 and 10.

<h3>2) x⁶ + x⁵ + x⁴ + x³ = 0 </h3>

Factor out the highest possible common term, applying the product rule of exponents, a^{m} a^{n} = a^{m+n}

x³ (x³ + x² + x¹ + 1) = 0

Next, apply the special factoring technique into the exponential expressions inside the parenthesis), the factor by grouping:

The factors for the given polynomial are: x³ (x² + 1) (x + 1)

<h3> 3) x² - 36 = 0 </h3>

Use the <u>difference of two squares factoring</u>, where it states: u² - v² = (u - v) (u + v)

Since 36 is a perfect square of 6², then we can establish the following factors using the difference of squares:

Factors:  (x - 6) (x + 6).

<h3>6) x² - x - 12 = 0 </h3>

For this quadratic trinomial, find factors that will produce a product of <em>a</em> × <em>c</em> (1 × -12) and sum of b (-1):

The possible factors of -12 that also results to a sum of -1 are:  

3 × -4 = -1

 Hence, the possible factors of x² - x - 12 = 0 could be (x + 3) (x - 4). Verify whether this is correct by performing the FOIL method:

(x + 3) (x - 4) = x² - 4x + 3x - 12 = x² - x - 12

Therefore, the factors of x² - x - 12 = 0 are: (x + 3) (x - 4).

<h3>8) 5x² - 7x - 6 = 0 </h3>

where a = 5, b = -7, and c = -6

Given this quadratic trinomial, we can use the factoring by grouping, where it states: find the values of u and v such that the product of uv is the same as the product of <em>ac</em>:  u × v = a × c, and that the sum of (<em>u</em> + <em>v </em>) is the same as <em>b</em>.  

In other words, we must find the factors of u × v that have a product of a × c and a sum of b:

<em>u × v </em>= <em>a × c</em> = 5 × (-6) = -30  

u + v = b = -7

The possible factors of -30 are:

-3 × 10 = -30

3 × -10 = -30

Out of these factors, the factors 3 × -10 = -30 will have the same sum as the value of b = -7:

3 + (-10) = -7

Hence, u = 3, v = -10.

Now, we can group the trinomial as follows:

(<em>ax</em>² + <em>ux </em>) + (<em>vx </em>+ <em>c </em>)

(5x² + 3x) + (-10x - 6)

For the last step, factor out the common terms from both groups:

(5x² + 3x) + (-10x - 6)  

x (5x + 3) - 2(5x + 3)

Combine common terms together: (5x + 3) and (x - 2)

Therefore, the factors of the given quadratic trinomial are: (5x + 3) (x - 2).

5 0
2 years ago
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