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masha68 [24]
3 years ago
8

In square ABCD, diagonal DB is drawn. If the m

Mathematics
1 answer:
pshichka [43]3 years ago
6 0

9514 1404 393

Answer:

  x = 11

Step-by-step explanation:

The diagonal creates two isosceles right triangles, so ...

  m∠CBD = 45°

  3x +12 = 45

  3x = 33 . . . . . . subtract 12

  x = 11 . . . . . . . . divide by 3

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aleksandrvk [35]

Answer:

its 2  

Step-by-step explanation:

so 6x2 is 12 and 5x2 is 10

u have to find the gcf of 12 and 10 which is 2 :)

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3 years ago
Can anyone help me with this problem?
Nadusha1986 [10]
What problem I cannot see The question
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If you are making a scale drawing of a girrafe that is 6m tall, and the height of the girrafe in your drawing is 3cm, what is th
k0ka [10]

Answer:

1cm to 200cm

Step-by-step explanation:

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3 years ago
Write one sine and one cosine equation for each graph below.
pychu [463]

Answer:

Q13. y = sin(2x – π/2); y = - 2cos2x  

Q14. y = 2sin2x -1; y = -2cos(2x – π/2) -1

Step-by-step explanation:

Question 13

(A) Sine function

y = a sin[b(x - h)] + k

y = a sin(bx - bh) + k; bh = phase shift

(1) Amp = 1; a = 1

(2) The graph is symmetrical about the x-axis. k = 0.

(3) Per = π. b = 2

(4) Phase shift = π/2.  

2h =π/2

h = π/4

The equation is

y = sin[2(x – π/4)} or

y = sin(2x – π/2)

B. Cosine function

y = a cos[b(x - h)] + k

y = a cos(bx - bh) + k; bh = phase shift

(1) Amp = 1; a = 1

(2) The graph is symmetrical about the x-axis. k = 0.

(3) Per = π. b = 2

(4) Reflected across x-axis, y ⟶ -y

The equation is y = - 2cos2x  

Question 14

(A) Sine function

(1) Amp = 2; a = 2

(2) Shifted down 1; k = -1

(3) Per = π; b = 2

(4) Phase shift = 0; h = 0

The equation is y = 2sin2x -1

(B) Cosine function

a = 2, b = -1; b = 2

Phase shift = π/2; h = π/4

The equation is

y = -2cos[2(x – π/4)] – 1 or

y = -2cos(2x – π/2) - 1

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3 years ago
The answer to: 3&lt;2p-3&lt;12
liq [111]
3<p<15/2 should be right
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