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3 years ago

5

All my poins for this algebra.Inga starts with K kitkat bars.She buys 5 more,and then gives half to her best friend.She finally

eats 2 of them herself.she ends up with ________ bars

1 answer:

pogonyaev3 years ago

4 0

Ends up=( K+5)1/2 -2 ends up=K/2+2.5-2=K(.5) + .5

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Plot the points (0,1), (-1,3), (2, -3) and describe the resulting graph.

ivanzaharov [21]

check the picture below.

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3 years ago

Use any of the methods to determine whether the series converges or diverges. Give reasons for your answer.

Aleks [24]

Answer:

It means $\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}$ also converges.

Step-by-step explanation:

The actual Series is::

$\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}$

The method we are going to use is comparison method:

According to comparison method, we have:

$\sum_{n=1}^{inf}a_n\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n$

If series one converges, the second converges and if second diverges series, one diverges

Now Simplify the given series:

Taking"n^2"common from numerator and "n^6"from denominator.

$=\frac{n^2[7-\frac{4}{n}+\frac{3}{n^2}]}{n^6[\frac{12}{n^6}+2]} \\\\=\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{n^4[\frac{12}{n^6}+2]}$

$\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n=\sum_{n=1}^{inf} \frac{1}{n^4}$

Now:

$\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\ \\\lim_{n \to \infty} a_n = \lim_{n \to \infty} \frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\=\frac{7-\frac{4}{inf}+\frac{3}{inf}}{\frac{12}{inf}+2}\\\\=\frac{7}{2}$

So a_n is finite, so it converges.

Similarly b_n converges according to p-test.

P-test:

General form:

$\sum_{n=1}^{inf}\frac{1}{n^p}$

if p>1 then series converges. In oue case we have:

$\sum_{n=1}^{inf}b_n=\frac{1}{n^4}$

p=4 >1, so b_n also converges.

According to comparison test if both series converges, the final series also converges.

It means $\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}$ also converges.

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3 years ago

Using a multiple of ten for at least one factor write an equation with a product that has four zeros

PtichkaEL [24]

Answer:

The required equation is : 5 · 4000 = 20,000

Step-by-step explanation:

We have to use multiple of 10 for at least one factor.

So, in order to form our equation, we take one factor as 4000 which is a multiple of 10 (10 × 400 = 4000)

And the other condition to form the equation is given that the product should contain 4 zeros, so we need to multiply the first factor 4000 by some number such that the product contains 4 zeros.

Therefore, if we multiply 4000 by 5 we get the product as 20000 which contains 4 zeros.

Hence, 5 × 4000 = 20,000 is our required equation.

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3 years ago

Hope has 3 pencils, 5 pens, and 7 erasers. Which fraction represents the

densk [106]

Answer:

1/3

Step-by-step explanation:

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3 years ago

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Maksim231197 [3]

Answer:

Midpoint of a line segment

(xM,yM) = (4, 5).

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3 years ago

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