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3 years ago

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In the Olympics, the athlete received an 85% score on the compulsory exercises, which are weighted 60%. In the optional round, w

eighted 40%, the athlete received a 90%. What was the athlete's weighted average score?

1 answer:

mote1985 [20]3 years ago

4 0

Answer:

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yKpoI14uk [10]

Answer:

it seems as if there are no numbers . try putting something in there.

Step-by-step explanation:

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3 years ago

Standerd form for 4,000 300 20 9

allochka39001 [22]

The number is 4329 your welcome

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4 years ago

Read 2 more answers

How to find angles on two Line intersect

Ivan

Hello!

Vertical angles are always congruent

This means that 3x - 35 = 130

We can solve this algebraically

3x - 35 = 130

Add 35 to both sides

3x = 165

Divide both sides by 3

x = 55

The angle AOB and AOC are supplementary which means they add to 180

First we have to find what angle AOB equals

3(55) - 35 = 130

We can subtract 180 by this number to get angle AOC

180 - 130 = 50

Angle AOC is 50

The answers are x = 55 and AOC = 50

Hope this helps!

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3 years ago

What are the zeros of , where <br><br> ? help please need some help someone help please

Crank

${ \boxed{\boxed{\begin{array}{cc} \maltese \bf \: given \\ \\ \rm \: f(x) = ( {x}^{2} + 16)( {x}^{2} - 9) \\ \\ \bf \: for \: zeroes \\ \\ \pink{ \boxed{\boxed{\begin{array}{c | c} \bf \: {x}^{2} + 16 = 0 & \bf \: {x}^{2} - 9 = 0 \\ \\ = > {x}^{2} = - 16& {x}^{2} = 9 \\ \\ = > x = \pm \sqrt{ - 16} &x = \pm \: \sqrt{9} \\ \\ = > x = \pm \sqrt{ {i}^{2} {4}^{2} } &x = \pm \: \sqrt{ {3}^{2} } \\ \\ = > x = \pm \: 4i&x = \pm3 \end{array}}}} \\ \\ \rm \: x = \pm3 \: and \pm \: 4i\end{array}}}}$

Option A is the correct answer

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3 years ago

The probability of an event

Readme [11.4K]

Answer:

d. is the sum of the probabilities of the sample points in the event.

Step-by-step explanation:

Suppose we have a fair coin then the the sample space S is given by {(H), (T)}

the head and tail are the sample points.

the probability of sample space will be given by the sum of probability of head and tail. P(S)= P(A) + P(B)

1= 1/2+ 1/2

The total probability of the sample space always equals 1

The individual probabilities add up to to give the probability of the sample space.

7 0

3 years ago