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3 years ago

15

which statement follows logically from the given statements? (1) if you like musicals, then you enjoy theater production.(2) if

your an actor, then you enjoy theater production

1 answer:

k0ka [10]3 years ago

8 0

Answer:

second one

Step-by-step explanation:

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The ______ of the degrees of each factor is

nasty-shy [4]

Answer:

B. Sum

Step-by-step explanation:

When finding the volume, we multiplied the 3 dimensions with degree of 1, 1 and 3 and got the binominal of degree 5. We summed up the degrees: 1 + 1 + 3 = 5.

The <u>SUM</u> of the degrees of each factor is the degree of the product.

8 0

3 years ago

Read 2 more answers

A representative from each of seven nations is to sit at a round table to discuss trade relations. How many ways can the represe

Sidana [21]

The correct answer is 720. Just turned it in and got a 100. Good luck and hoped this help ya.

7 0

3 years ago

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Find the constant of variation (k) for the inverse variation. Then write an equation for the inverse situation.

notka56 [123]

y = k/x

5 =k/7.5

k = 7.5/*5= 37.5

answer is D

7 0

3 years ago

Read 2 more answers

Factorise fully x^3-x

MA_775_DIABLO [31]

Answer:

$x(x+1)(x-1)$

Step-by-step explanation:

We see that the two terms share an x, so we can pull that out:

$x^3-x=x(x^2-1)$

Now notice that we have a difference of squares ( $x^2-1$ ). Given a difference of squares, $a^2-b^2$ , this can always be factored into $(a+b)(a-b)$ . We can use this in this case: $x^2-1=(x+1)(x-1)$ .

So, our final factorized form is: $x(x+1)(x-1)$ .

Hope this helps!

3 0

3 years ago

15. If x=a Sin2t (I+Cos2t) and y=b Cos 2t (1-Cos2t) then find<br>dy/dx at =22/7*4<br>

Sav [38]

By the chain rule,

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm dt}\dfrac{\mathrm dt}{\mathrm dx}\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm dt}}{\frac{\mathrm dx}{\mathrm dt}}$

It looks like we're given

$\begin{cases}x=a\sin(2t)(1+\cos(2t))\\y=b\cos(2t)(1-\cos(2t))\end{cases}$

where <em>a</em> and <em>b</em> are presumably constant.

Recall that

$\cos^2t=\dfrac{1+\cos(2t)}2$

$\sin^2t=\dfrac{1-\cos(2t)}2$

so that

$\begin{cases}x=2a\sin(2t)\cos^2t\\y=2b\cos(2t)\sin^2t\end{cases}$

Then we have

$\dfrac{\mathrm dx}{\mathrm dt}=4a\cos(2t)\cos^2t-4a\sin(2t)\cos t\sin t$

$\dfrac{\mathrm dy}{\mathrm dt}=-4b\sin(2t)\sin^2t+4b\cos(2t)\sin t\cos t$

$\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{4b\cos(2t)\sin t\cos t-4b\sin(2t)\sin^2}{4a\cos(2t)\cos^2t-4a\sin(2t)\cos t\sin t}$

$\implies\boxed{\dfrac{\mathrm dy}{\mathrm dx}=\dfrac ba\tan t}$

where the last reduction follows from dividing through everything by $\cos(2t)\cos^2t$ and simplifying.

I'm not sure at which point you're supposed to evaluate the derivative (22/7*4, as in 88/7? or something else?), so I'll leave that to you.

8 0

3 years ago