(C) 
fraction of the marbles now in the bag is blue.
<h3>
What is a fraction?</h3>
- A fraction is a portion of a whole or, more broadly, any number of equal parts.
- In everyday English, a fraction represents the number of pieces of a specific size, such as one-half, eight-fifths, or three-quarters.
- A common, vulgar, or simple fraction that consists of a numerator above a line and a non-zero denominator below that line.
- Numerators and denominators are also employed in uncommon fractions such as compound fractions, complex fractions, and mixed numerals.
To find what fraction of the marbles now in the bag is blue:
- Important information is that immediately before the last step blue marbles formed
from the marble in the bag. - That means that there were
blue and 
other marbles, for some . - When we double the number of blue marbles, there will be
blue and other marbles. - Hence, blue marbles now form all marbles in the bag.
Therefore, (C) fraction of the marbles now in the bag is blue.
Know more about fractions here:
brainly.com/question/17220365
SPJ4
Complete question:
A bag initially contains red marbles and blue marbles only, with more blue than red. Red marbles are added to the bag until only 1 / 3 of the marbles in the bag are blue. Then yellow marbles are added to the bag until only 1 / 5 of the marbles in the bag are blue. Finally, the number of blue marbles in the bag is doubled. What fraction of the marbles now in the bag are blue?
(A) 1/5
(B) 1/4
(C) 1/3
(D) 2/5
(E) 1/2
Answer:
12 + 24 = 2(6 + 12)
Step-by-step explanation:
hope this helpss :D
much appreciated if this were marked brainliest <3
Answer and Explanation:
A function is said to be increasing, if the derivative of function is f’(x) > 0 on each point. A function is said to be decreasing if f”(x) < 0.
Let y = v (z) be differentiable on the interval (a, b). If two points z1 and z2 belongs to the interval (a, b) such that z1 < z2, then v (z1) ≤ v (z2), the function is increasing in this interval.
Similarly, the function y = v(z) is said to be decreasing, when it is differentiable on the interval (a , b).
Two points z1 and z2 Є (a, b) such that z1 > z2, then v (z1) ≥ v(z2). The function is decreasing on this interval.
The function y = v (z)
The derivative of function Y’ = v’(z) is positive, then the function is increasing.
The function y = v (z)
The derivative of function y’ is negative, then the function is decreasing.
Answer:
x is 90° I hope it will help you please follow me
Let's write the equation in standard from
Where,
- m is slope or rate of change
- b is the y-intercept or initial value
<h3>Let's start by finding slope⤵️</h3>
- x1, y1 = 0,12
- x2, y2 = 1,13
<h3>Equation⤵️</h3>
