Answer:
The value of f(1) is smaller than the value of f(3)
Step-by-step explanation:
<u><em>The correct question is</em></u>
Given the function f(x) = 2x^2 + 3x + 10, find f(1) and f(3). Choose the statement that is true concerning these two values.
The value of f(1) is the same as the value of f(3).
The value of f(1) cannot be compared to the value of f(3).
The value of f(1) is larger than the value of f(3).
The value of f(1) is smaller than the value of f(3)
we have
step 1
Find out the value of f(1)
substitute the value of x=1 in the function f(x)
so
For x=1
step 2
Find out the value of f(3)
substitute the value of x=3 in the function f(x)
so
For x=3
step 3
Compare the values
37> 15
so
f(3) > f(1)
or
f(1) < f(3)
therefore
The value of f(1) is smaller than the value of f(3)
Answer:
2 dollars
Step-by-step explanation:
For 4 pounds of fruit he pays 8 dollars. If you use the unit rate it is 2 dollars for every one pound of fruit
keeping in mind that 4 months is not even a year, since there are 12 months in a year, 4 months is then 4/12 years.
let's assume is simple interest.
![\bf ~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$34300\\ r=rate\to 3.5\%\to \frac{3.5}{100}\dotfill &0.035\\ t=years\to \frac{4}{12}\dotfill &\frac{1}{3} \end{cases} \\\\\\ A=34300\left[ 1+(0.035)\left( \frac{1}{3} \right) \right]\implies A= 34300(1.011\overline{6})\implies A=34700.1\overline{6}](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%20%5Ctextit%7BSimple%20Interest%20Earned%20Amount%7D%20%5C%5C%5C%5C%20A%3DP%281%2Brt%29%5Cqquad%20%5Cbegin%7Bcases%7D%20A%3D%5Ctextit%7Baccumulated%20amount%7D%5C%5C%20P%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5Cdotfill%20%26%20%5C%2434300%5C%5C%20r%3Drate%5Cto%203.5%5C%25%5Cto%20%5Cfrac%7B3.5%7D%7B100%7D%5Cdotfill%20%260.035%5C%5C%20t%3Dyears%5Cto%20%5Cfrac%7B4%7D%7B12%7D%5Cdotfill%20%26%5Cfrac%7B1%7D%7B3%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20A%3D34300%5Cleft%5B%201%2B%280.035%29%5Cleft%28%20%5Cfrac%7B1%7D%7B3%7D%20%5Cright%29%20%5Cright%5D%5Cimplies%20A%3D%2034300%281.011%5Coverline%7B6%7D%29%5Cimplies%20A%3D34700.1%5Coverline%7B6%7D)
Answer:
99% Confidence interval: (1196,1973)
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 20
Mean, μ = 1584
Standard Deviation, σ = 607
99% Confidence interval:
Putting the values, we get,
Thus, there is a 99% chance that it will break in approximately 1196 to 1972
Answer:
Step-by-step explanation:
Let X be the monthly count of salmonellosis cases in South Dakota.
And X has Poisson(A 1.62)
E(X) = \lambda = 1.62
Var(X) = \lambda = 1.62
Standard Deviation (X) = \sqrt{\lambda} = \sqrt{1.62} = 1.27
c)
Mean of salmonellosis cases in South Dakota over a six month period is = 6*1.62 = 9.72
standard deviation of salmonellosis cases in South Dakota over a six month period is = 6*1.27 = 7.62
