1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
liraira [26]
2 years ago
6

Is a rule that assigns each value of the independent valable to

Mathematics
1 answer:
MA_775_DIABLO [31]2 years ago
4 0

Answer:

For different x values ,we get unique y value. So, Yes the Statement is true that , A function is a rule that assigns each value of the independent variable to exactly one value of the dependent variable.

Step-by-step explanation:

You might be interested in
Q bisects PR, PQ=3y, and PR=42. Find y and QR.
Vedmedyk [2.9K]
|PR| = |PQ| + |QR|; |PQ| = |QR| conclusion |PR| = 2|PQ|

|PQ| = 3y; |PR| = 42; |QR|=?

subtitute

42 = 2(3y)
6y = 42    |divide both sides by 6
y = 7

|QR| = 3(7) = 21
3 0
3 years ago
Given the function f(x)=4x^8+7x^7+1x^6+1 What is the value of f(−2)?
qwelly [4]
<span> f(x)=4x^8+7x^7+1x^6+
</span>∴<span> f(-2)=4(-2)^8+7(-2)^7+1(-2)^6+1
</span>∴ <span>f(-2)=(4x256) + (7x-128) + (1x64) +1
</span>∴ <span>f(-2)=1024 - 896 + 64 +1
</span>∴ <span>f(-2)= 193</span>
7 0
3 years ago
Point A(1, 4) reflected over the line x = y. What is the coordinate of A’?
alisha [4.7K]

Answer:

I believe the answer is (-4,-1)

Step-by-step explanation:

6 0
3 years ago
The surface area of a right circular cone of radius r and height h is S = πr√ r 2 + h 2 , and its volume is V = 1 3 πr2h. What i
kirill115 [55]

Answer:

Required largest volume is 0.407114 unit.

Step-by-step explanation:

Given surface area of a right circular cone of radious r and height h is,

S=\pi r\sqrt{r^2+h^2}

and volume,

V=\frac{1}{3}\pi r^2 h

To find the largest volume if the surface area is S=8 (say), then applying Lagranges multipliers,

f(r,h)=\frac{1}{3}\pi r^2 h

subject to,

g(r,h)=\pi r\sqrt{r^2+h^2}=8\hfill (1)

We know for maximum volume r\neq 0. So let \lambda be the Lagranges multipliers be such that,

f_r=\lambda g_r

\implies \frac{2}{3}\pi r h=\lambda (\pi \sqrt{r^2+h^2}+\frac{\pi r^2}{\sqrt{r^2+h^2}})

\implies \frac{2}{3}r h= \lambda (\sqrt{r^2+h^2}+\frac{ r^2}{\sqrt{r^2+h^2}})\hfill (2)

And,

f_h=\lambda g_h

\implies \frac{1}{3}\pi r^2=\lambda \frac{\pi rh}{\sqrt{r^2+h^2}}

\implies \lambda=\frac{r\sqrt{r^2+h^2}}{3h}\hfill (3)

Substitute (3) in (2) we get,

\frac{2}{3}rh=\frac{r\sqrt{R^2+h^2}}{3h}(\sqrt{R^2+h^2+}+\frac{r^2}{\sqrt{r^2+h^2}})

\implies \frac{2}{3}rh=\frac{r}{3h}(2r^2+h^2)

\implies h^2=2r^2

Substitute this value in (1) we get,

\pi r\sqrt{h^2+r^2}=8

\implies \pi r \sqrt{2r^2+r^2}=8

\implies r=\sqrt{\frac{8}{\pi\sqrt{3}}}\equiv 1.21252

Then,

h=\sqrt{2}(1.21252)\equiv 1.71476

Hence largest volume,

V=\frac{1}{3}\times \pi \times\frac{\pi}{8\sqrt{3}}\times 1.71476=0.407114

3 0
2 years ago
A system of linear equations has how many solutions when the graphs intersect at a point.
pav-90 [236]
Answer: One solution Explanation: just did this lesson a day ago
7 0
2 years ago
Other questions:
  • mark transferred songs from his computer onto his portable music player. He transferred 2 6/7 songs in 1 2/3 minutes. How many s
    11·2 answers
  • Vector u = &lt;11, 12&gt;, v = &lt;-16, 6&gt;, and w = &lt;4, -5&gt;.
    13·1 answer
  • Given that a randomly chosen customer like cakes what is the probability that the customer also likes pie
    12·2 answers
  • Estimate the decimal factors, then multiply to estimate the product. 1. 5.3 rounded to the nearest whole number is ____ . 2. 7.9
    15·2 answers
  • Find the slope of the following equation: y = 5 - 2.x​
    7·1 answer
  • Simplify 5-2•3+4<br> A)13<br> B)-5<br> C)3<br> D)21
    5·1 answer
  • How do you multiply 45 times 52
    13·2 answers
  • Get your 50 bucks here!!
    9·2 answers
  • The sum of two different prime numbers is always prime counterexample
    11·2 answers
  • If 9: x= x4, then x=
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!