|PR| = |PQ| + |QR|; |PQ| = |QR| conclusion |PR| = 2|PQ|
|PQ| = 3y; |PR| = 42; |QR|=?
subtitute
42 = 2(3y)
6y = 42 |divide both sides by 6
y = 7
|QR| = 3(7) = 21
<span> f(x)=4x^8+7x^7+1x^6+
</span>∴<span> f(-2)=4(-2)^8+7(-2)^7+1(-2)^6+1
</span>∴ <span>f(-2)=(4x256) + (7x-128) + (1x64) +1
</span>∴ <span>f(-2)=1024 - 896 + 64 +1
</span>∴ <span>f(-2)= 193</span>
Answer:
I believe the answer is (-4,-1)
Step-by-step explanation:
Answer:
Required largest volume is 0.407114 unit.
Step-by-step explanation:
Given surface area of a right circular cone of radious r and height h is,
and volume,

To find the largest volume if the surface area is S=8 (say), then applying Lagranges multipliers,
subject to,

We know for maximum volume
. So let
be the Lagranges multipliers be such that,



And,



Substitute (3) in (2) we get,



Substitute this value in (1) we get,



Then,

Hence largest volume,

Answer: One solution Explanation: just did this lesson a day ago