All categories

3 years ago

Find three consecutive integers whose sum is 1266

Mathematics

1 answer:

Gre4nikov [31]3 years ago

6 0

Answer:

(x)t(xt1)t(xt2)=1266

Step-by-step explanation:

here here we will use the algebra to find three consecutive integers whose sum is 1266 we start by assigning x to the first integer since there are consecutive it means that the second number will be x plus 1 and the third will be x plus 2 they shall all add up to 1 2 6 6 therefore you can write the equation as a following

You might be interested in

What is the median of this list of numbers? 22, 18, 23, 36, 26, 18, 29. A. 22 B. 18 C. 23 D. 36

7nadin3 [17]

Answer:

C. 23

Step-by-step explanation:

18 18 22 23 26 29 36

23 is in the middle

5 0

2 years ago

How many digits of pi does it take to add up to 14, 25, 68, 103, and 150? I am being timed, whoever answers this fast or quick I

Mandarinka [93]

Answer:

to get 14 first 5 digits

to get to 25 first 7 digits

to get to 68 first 14 digits

to get to 103 first 21 digits

to get to 150 first 31 digits

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Given h (x) = -x-4,solve for x when h (x) =9

Leona [35]

Answer:

–13

Step-by-step explanation:

h(x) = –x –4

h(x) = 9

–x –4 = 9

–x = 9 + 4

–x = 13

x = –13

<em><u>pick me as the brainliest. thx</u></em>

8 0

2 years ago

Please help and explain I'll give u 12pts

White raven [17]

-7x² + 70x - 175

= -7(x² - 10x + 25)

= -7(x - 5)²

= -7(x + -5)²

Answer: -5

7 0

2 years ago

I need this answer fast! Please!

vovangra [49]

Answer:

$\large\boxed{\begin{array}{c|c|c|c}Length:&4cm&2cm&8cm\\Width:&6cm&12cm&3cm\\Height:&9cm&9cm&9cm\end{array}}$

Step-by-step explanation:

The formula of a volume of a cube with side length a:

$V=a^3$

We have a = 6cm. Substitute:

$V=6^3=216\ cm^3$

$\begin{array}{c|c}216&2\\108&2\\54&2\\27&3\\9&3\\3&3\\1\end{array}$

$216=2\cdot2\cdot2\cdot3\cdot3\cdot3=(2\cdot2)\cdot(2\cdot3)\cdot(3\cdot3)=4\cdot6\cdot9\\\\216=2\cdot2\cdot2\cdot3\cdot3\cdot3=2\cdot(2\cdot2\cdot3)\cdot(3\cdot3)=2\cdot12\cdot9\\\\216=2\cdot2\cdot2\cdot3\cdot3\cdot3=(2\cdot2\cdot2)\cdot3\cdot(3\cdot3)=8\cdot3\cdot9\\\vdots$

7 0

2 years ago