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USPshnik [31]
3 years ago
15

HELP ASAP George plans to cover his circular pool for the upcoming winter season. The pool has a diameter of 20 feet and extends

12 inches beyond the edge of the pool. A rope runs along the edge of the cover to secure it in place.
a.
What is the area of the pool cover?
b.
What is the length of the rope?
Mathematics
1 answer:
enyata [817]3 years ago
3 0
The pool has a diameter 20 ft so:  r = 10 ft.
The pool cover extents 12 inches beyond the edge of the pool. 
12 inches = 1 foot
Therefore, the radius of the pool cover is : r = 10 + 1 = 11 ft.
a. The area of the pool cover:
A = r² π = 11² π = 121 π ft²
b.  The length of the rope:
l = 2 r π = 2 · 11 π = 22 π ft.
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Answer:

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Step-by-step explanation:

distance = sqrt ((x2-x1)^2+(y2-y1)^2)

We know Point B and the x coordinate of point A as well as the distance

15 = sqrt ((-4-5)^2+(-2-y1)^2)

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Take the square root of each side

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Add 2 to each side

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Multiply by -1

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The y coordinates for A are either 10 or -14

Now move B to -7,-2

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15 = sqrt (144+(-2-y1)^2)

Square each side

15^2 =sqrt (144+(-2-y1)^2)^2

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Subtract 144 from each side

225-144 = 144-144 +(-2-y1)^2

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Take the square root of each side

±sqrt 81 = sqrt(-2-y1)^2

±9 = (-2-y1)

Add 2 to each side

2±9 = 2-2-y1

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Multiply by -1

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