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USPshnik [31]
3 years ago
15

HELP ASAP George plans to cover his circular pool for the upcoming winter season. The pool has a diameter of 20 feet and extends

12 inches beyond the edge of the pool. A rope runs along the edge of the cover to secure it in place.
a.
What is the area of the pool cover?
b.
What is the length of the rope?
Mathematics
1 answer:
enyata [817]3 years ago
3 0
The pool has a diameter 20 ft so:  r = 10 ft.
The pool cover extents 12 inches beyond the edge of the pool. 
12 inches = 1 foot
Therefore, the radius of the pool cover is : r = 10 + 1 = 11 ft.
a. The area of the pool cover:
A = r² π = 11² π = 121 π ft²
b.  The length of the rope:
l = 2 r π = 2 · 11 π = 22 π ft.
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Answer:

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Step-by-step explanation:

* Lets talk about dilation

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* In the problem

∵ Δ ABC is dilated by a scale factor of 3 with the origin as the center

  of dilation

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3 years ago
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alex41 [277]

Hey there!!

Let us take the first number as ' x '

According to the question

The second number exceeds the first number by 15

hence, the second number = x+15

The sum of both the numbers = 69

which means

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2x+15 = 69

Subtracting by 15 on both sides

2x + 15 - 15 = 69 - 15

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dividing by  2 on both sides

x = 27

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Hope my answer helps!

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Answer:

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