The greatest number of sets would be 20 with one girl and one boy in each.
Answer:
As x decreases without bound, f(x) increases without bound
As x increases without bound, f(x) approaches 0
Step-by-step explanation:
As x gets more and more negative f(x) gets bigger and bigger
f(x) = (7/10) ^ x but x is negative so flip it and then x is a larger number
(10/7) ^ large number so it will get larger
as → -∞ f(x) →∞
As x gets more and more positive f(x) gets smaller and smaller
f(x) = (7/10) ^ x closer and closer to 0. The denominator gets larger faster than the numerator = 1 / large number
as → ∞ f(x) →0
2y+4=3(y-1)
2y+4=3y-3
4+3=3y-2y
Y=7
X=2
<span>The answers to this problem are:<span>(<span>±5</span></span>√3/8,±5/8)<span>Here is the solution:
Step 1: <span><span><span>x2</span>+<span>y2</span>=<span>2516</span>[2]</span><span><span>x2</span>+<span>y2</span>=<span>2516</span>[2]</span></span>
Step 2: Substitute:<span>
</span><span><span>8<span><span>(<span>25/16</span>)^</span>2</span>=25(<span>x^2</span>−<span>y^2</span>)
</span><span>8<span><span>(<span>25/16</span>)^</span>2</span>=25(<span>x^2</span>−<span>y^2</span>)</span></span>
</span><span>x^2</span>−<span>y^2</span>=<span>25/32</span><span>.
Add [2] and [3]:<span>
</span><span>2<span>x^2</span>=<span>75/32
</span><span>x^2</span>=<span>75/74</span></span>
<span>x=±5</span></span>√3/8<span>
Substitute into [2]:<span>
</span><span><span>75/64</span>+<span>y^2</span>=<span>50/32
</span><span>y^2</span>=<span>25/64</span></span>
<span>y=±<span>5/8</span></span>
</span>
</span>
