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3 years ago

|9(1) 9(1) = 50 g(n) = 8 – g(n − 1) g(2) = What’s g(2)

Mathematics

1 answer:

seraphim [82]3 years ago

8 0

this is confusing

can someone exp;ain this

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Find the area of a trapezium shaped table whose parallel sides are 6 metre and 8 metre and the distance between the parallel sid

katovenus [111]

Length of parallel sides=8 cm, 9 cm
Distance between parallel sides=6 cm
Area =
2
1

(distance between parallel sides)× (sum of parallel sides)
=
2
1

×6×(8+9)
=3×17=51

hope it helps

5 0

3 years ago

Determine whether a triangle can be formed with the given side lengths. If the side lengths

scoundrel [369]

Answer:

it can't form isosceles triangle cause any two sides of the triangle are not equal ,it can't form equalateral triangle cause 3 sides of the triangle are not equal and neither right angle triangle so triangle can't be formed

7 0

3 years ago

Match the expressions with their equivalent simplified expressions.

Tasya [4]

Answer:

$\sqrt[4]{\frac{16x^6y^4}{81x^2y^8}}\rightarrow\frac{2x}{3y}\\\sqrt[4]{\frac{81x^2y^{10}}{81x^6y^6}} \rightarrow\frac{3y}{2x}\\\sqrt[3]{\frac{64x^8y^7}{125x^2y^{10}}}\rightarrow\frac{4x^2}{5y}\\\sqrt[5]{\frac{243x^{17}y^{16}}{32x^7y^{21}}}\rightarrow\frac{3x^2}{2y}\\\sqrt[5]{\frac{32x^{12}y^{15}}{243x^7y^{10}}} \rightarrow\frac{2xy}{3}\\\sqrt[4]{\frac{16x^{10}y^{9}}{256x^2y^{17}}}\rightarrow\frac{x}{2y}$

Step-by-step explanation:

$\sqrt[4]{\frac{16x^6y^4}{81x^2y^8}} =\sqrt[4]{\frac{(2^4)(x^{6-2})(y^{4-8})}{(3^4)}} =\sqrt[4]{\frac{2^4x^4y^{-4}}{3^4}} =\frac{2xy^{-1}}{3}=\frac{2x}{3y}$

$\sqrt[4]{\frac{81x^2y^{10}}{81x^6y^6}} =\sqrt[4]{\frac{(3^4)(x^{2-6})(y^{10-6})}{(2^4)}} =\sqrt[4]{\frac{3^4x^{-4}y^{4}}{2^4}} =\frac{3x^{-1}y^1}{3}=\frac{3y}{2x}$

$\sqrt[3]{\frac{64x^8y^7}{125x^2y^{10}}} =\sqrt[3]{\frac{(4^3)(x^{8-2})(y^{7-10})}{(5^3)}} =\sqrt[3]{\frac{4^3x^6y^{-3}}{5^3}} =\frac{4x^2y^{-1}}{5}=\frac{4x^2}{5y}$

$\sqrt[5]{\frac{243x^{17}y^{16}}{32x^7y^{21}}} =\sqrt[5]{\frac{(3^5)(x^{17-7})(y^{16-21})}{(2^5)}} =\sqrt[5]{\frac{3^5x^{10}y^{-5}}{2^5}} =\frac{3x^2y^{-1}}{2}=\frac{3x^2}{2y}$

$\sqrt[5]{\frac{32x^{12}y^{15}}{243x^7y^{10}}} =\sqrt[5]{\frac{(2^5)(x^{12-7})(y^{15-10})}{(3^5)}} =\sqrt[5]{\frac{2^5x^{5}y^{5}}{3^5}} =\frac{2x^1y^{1}}{3}=\frac{2xy}{3}$

$\sqrt[4]{\frac{16x^{10}y^{9}}{256x^2y^{17}}} =\sqrt[4]{\frac{(2^4)(x^{10-2})(y^{9-17})}{(4^4)}} =\sqrt[4]{\frac{2^4x^{8}y^{-8}}{4^4}} =\frac{2x^{1}y^{-1}}{4}=\frac{x}{2y}$

Thus,

3 0

3 years ago

Please help it’s lines

JulijaS [17]

I think the answer is c, 88
Hope this helps :)

6 0

3 years ago

The proportion of students in a psychology experiment who could remember an eight-digit number correctly for t minutes was 0.9 −

kaheart [24]

Answer:

The proportion would be 0.1

Step-by-step explanation:

Given, the function that shows the proportion of students in a psychology experiment who could remember an eight-digit number correctly for t minutes,

$f(t) = 0.9 - 0.4\ln(t)$

If t = 7 minutes,

$f(7) = 0.9 - 0.4\ln(7)=0.9 - 0.77836=0.12164\approx 0.1$

Hence, the proportion that remembered the number for 7 minutes is 0.1 ( approx )

8 0

3 years ago