Answer:
m∠BCD = 140°
Step-by-step explanation:
ABCD is cyclic quadrilateral. A property of cyclic quadrilateral states that the opposite angles of it sum up to 180°. Here:
m∠A + m∠C =180° and m∠B + m∠D = 180°
So, m∠A + m∠C =180°
m∠A = 40° (given in the question)
40° + m∠C = 180°
m∠C = 180° - 40° = 140°
∴m∠C = m∠BCD = 140°
First, 9.8 (Gravity) times 3 (time) equals 29.4, which is the velocity after 3 seconds. The kinematic equation for change in position that uses the variables we have is:
delta x= (v)(t) -0.5(acceleration)(time)^2
delta x= 29.4 times (3) - 0.5 (9.8) times 9
delta x= 44.1
100 minus 44.1 equals 55.9, which is the answer for part a.
Tell me if you need any clarification
PART B:
The kinematic equation for this is:
delta x= (initial velocity) times time plus 0.5 (a)(time)^2
100=(0)times(x) plus 0.5 (a)(time)^2
100=0.5(9.8)(x)^2
100=4.9x^2
100/4.9 is approxamitely 20.4.
The squareroot of this is approxamitely 4.5.
4.5 seconds
Tell me if you need any clarification
A. the first one is the answer
Step-by-step explanation:
25% should be the answer, let me kno if its correct
Answer:
Step-by-step explanation:
Start
<F = <Q Given
<GPF = <RPQ Vertically opposite angles
<FGP = <QRP A triangle has 180 degrees. 2 equal angles means the third pair must be equal
Triangle GPF ~ Triangle RPQ AAA
end
I don't see any way to make these triangles similar except by stating the statement and why it is so. There really are no yes / no choices. If you get another answer, choose it.
20
JL/LE = 90/27 Given
KL /LD = 90/27 Given
<JLK = <DLK Vertically opposite
Are the ratios equal Yes Then is the angle included Yes
Then the triangles are similar.
Are the ratios not equal No then the triangles cannot be similar
Is the angle not included Then similarity cannot be proved.
ΔJLK ≈ ΔDLK Equal Ratios and included angle === similarity
