Given two functions are
f(x) = 2 cos(x)
g(x) = 3 sin(x+
)
We know that the maximum value of cos x and sin x is always 1
y= maximum of cos = 1
y= maximum of sin =1
f(x) = 2 cos(x)
y= 2 (max of cos) = 2(1) = 2
g(x) = 3 sin(x+
)
y= 3 (max of sin) = 3(1) = 3
g(x) = 3 sin(x+
) has the maximum value.
The value of constant c for which the function k(x) is continuous is zero.
<h3>What is the limit of a function?</h3>
The limit of a function at a point k in its field is the value that the function approaches as its parameter approaches k.
To determine the value of constant c for which the function of k(x) is continuous, we take the limit of the parameter as follows:


Provided that:

Using l'Hospital's rule:

Therefore:

Hence; c = 0
Learn more about the limit of a function x here:
brainly.com/question/8131777
#SPJ1
I assume you're looking for n.
so, take 2n/10-3n/10=2/10. Making everything have the same denominator is always easier.
This way, you have -n/10=2/10.
n=-2.
You multiply radius by 3.14 by the height if you plug it in your equation is 8×3.14×15 which equals 1005.31 which rounds to 1005, the answer is 1005! :D