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Stolb23 [73]
2 years ago
7

Consider the following steady, two-dimensional velocity field: V→(u,v) = (0.46 + 2.1x)i→ + (−2.8 - 2.1y)j→ Calculate the locatio

n of the stagnation point. The location of the stagnation points are x = and y = .
Mathematics
1 answer:
Elodia [21]2 years ago
4 0

Answer:

there is no stagnation point

Step-by-step explanation:

for the velocity field V→(u,v)= (0.46 + 2.1x)i→ + (−2.8 - 2.1y)j , the stagnation point is found when the velocity vectors converge in one point ( thus also stays in that place when the point is reached). Thus the stagnation point can be found when the divergence of the velocity field is <0 ( thus it does not diverge , but converges)

div(V) = ∇*V= d/dx (0.46 + 2.1x) + d/dy (−2.8 - 2.1y) = 0

2.1 - 2.1 = 0

since div(V) can never be  <0 , there is no stagnation point

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<em>Step-by-step explanation:</em>

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8 0
3 years ago
4380 rounded to the nearest 100​
maks197457 [2]

4,400

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4 0
3 years ago
Read 2 more answers
A professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their class
KIM [24]

Answer:

We conclude that seniors skip more than 2% of their classes at 0.01 level of significance.

Step-by-step explanation:

We are given that a professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their classes.

He randomly samples a group of seniors and out of 2521 classes, the group skipped 77.

<u><em /></u>

<u><em>Let p = percentage of seniors who skip their classes.</em></u>

So, Null Hypothesis, H_0 : p \leq 2%   {means that seniors skip less than or equal to 2% of their classes}

Alternate Hypothesis, H_A : p > 2%   {means that seniors skip more than 2% of their classes}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                   T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = sample proportion of seniors who skipped their classes = \frac{77}{2521}

           n = sample of classes = 2521

So, <u><em>test statistics</em></u>  =  \frac{\frac{77}{2521} -0.02}{{\sqrt{\frac{\frac{77}{2521}(1-\frac{77}{2521})}{2521} } } } }

                               =  3.08

The value of the test statistics is 3.08.

Now at 0.01 significance level, <u>the z table gives critical value of 2.3263 for right-tailed test</u>. Since our test statistics is more than the critical value of z as 2.3263 < 3.08, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that seniors skip more than 2% of their classes.

6 0
3 years ago
&lt;br /&gt;How do I solve 2x+y=10
ololo11 [35]
X is 3 y is 4 hope this helps :)
7 0
2 years ago
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Tim spent $37.45 on groceries. On the way home, he wants to stop and pay cash for gas at $3.35 per gallon. If he started with $6
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Answer:

6.7

Step-by-step explanation:

60$-37.45=22.55

22.55/3.35=6.731

Which rounds to 6.7

5 0
3 years ago
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