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Stolb23 [73]
3 years ago
7

Consider the following steady, two-dimensional velocity field: V→(u,v) = (0.46 + 2.1x)i→ + (−2.8 - 2.1y)j→ Calculate the locatio

n of the stagnation point. The location of the stagnation points are x = and y = .
Mathematics
1 answer:
Elodia [21]3 years ago
4 0

Answer:

there is no stagnation point

Step-by-step explanation:

for the velocity field V→(u,v)= (0.46 + 2.1x)i→ + (−2.8 - 2.1y)j , the stagnation point is found when the velocity vectors converge in one point ( thus also stays in that place when the point is reached). Thus the stagnation point can be found when the divergence of the velocity field is <0 ( thus it does not diverge , but converges)

div(V) = ∇*V= d/dx (0.46 + 2.1x) + d/dy (−2.8 - 2.1y) = 0

2.1 - 2.1 = 0

since div(V) can never be  <0 , there is no stagnation point

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