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IceJOKER [234]
3 years ago
14

Find all the missing measurement​

Mathematics
1 answer:
AveGali [126]3 years ago
6 0

Answer:

<h2>find all the missing measurement</h2>

You might be interested in
Which equation is equivalent to 16 Superscript 2 p Baseline = 32 Superscript p 3?.
Mrac [35]

The equation which is equivalent to 16 Superscript 2 p Baseline equal to 32 Superscript p 3 is,

2^{8p}=2^{5p+15}

<h3>What is equivalent equation?</h3>

Equivalent equation are the expression whose result is equal to the original expression, but the way of representation is different.

Given information-

The given equation in the problem is,

16^{2p}=32^{p+3}

Write both the equation in the form of same base number as,

(2^4)^{2p}=(2^5)^{p+3}

The power of the power of a number can be written as product of both the numbers. Thus,

(2)^{4\times2p}=(2)^{5\times(p+3)}\\2^{8P}=2^{5P+15}

This is the required equation.

Now if the base is the same at both side of the expression, then the powers can be compared. Thus,

8p=5p+15

Solve it further to find the value of p as,

8p-5p=15\\3p=15\\p=5

Thus the equation which is equivalent to 16 Superscript 2 p Baseline equal to 32 Superscript p 3 is,

2^{8p}=2^{5p+15}

Learn more about the equivalent expression here;

brainly.com/question/2972832

7 0
2 years ago
How describe a shape of a graph
My name is Ann [436]

You can describe them by Charts and lines or if it has a single peak

7 0
3 years ago
A polynomial with rational coefficients has roots 5 and -6i. (The i is an imaginary number not variable). What is the polynomial
mars1129 [50]

Answer:

<em>The answer is</em>  <em>{x^{3}-(5)x^{2} (36)× x-(180)</em>

Step-by-step explanation:

   A polynomial with rational coefficients has roots 5 and -6i (There i is the    

   imaginary number not variable )

   As we knew that imaginary no comes in pair . This means that if  -6i is

   one root then the other root will be 6i

   So if we assume the lowest polynomial that is possible is given as

    {x^{3}-(sum of all roots)x^{2} +(roots taken two at a time)

    x-(product of all roots)

    {x^{3}-(5+6i+(-6i))x^{2} +(5×6i +5×(-6i) +6i×(-6i))

    x-(5×6i×(-6i))

    i^2 = -1

    <em>{x^{3}-(5)x^{2} (36)× x-(180)</em>

<em>    </em>The <u>general case</u> we assume that the three previous roots and rest roots

   a4,a5,a6 ...............an

  x^n-(sum of all roots)×x^{n-1} +(roots taken two at a  

   time) ×x^{n-2}- .......................................... (product of all roots)

3 0
3 years ago
2(4x-5)-3<br><br> Math Help<br><br> Simplify the expression
Anvisha [2.4K]
8x-13


2(4)=8
2(-5)=-10
-10-3=-13
7 0
3 years ago
Write and solve a measure of each angle.
aliya0001 [1]
They both are acute angles
8 0
3 years ago
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