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Nookie1986 [14]
3 years ago
8

Describe how to determine the average rate of change between x=1 and x=3 for the function f(x)=3x^3+1. Include the average rate

of change in your answer.
Mathematics
1 answer:
icang [17]3 years ago
7 0

Answer:

39.

Step-by-step explanation:

We subtract  f(1) which is the value of f(x) when x = 1 from f(3),  then we divide by 3 - 1.

It is [(f3) - f(1]) / (3 - 1), so

Average rate of change = (3(3)^3 + 1) - (3(1)^3 + 1) / (3 - 1)

= (82 - 4) / 2

= 78 / 2

=  39.

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Read and follow the directions below. 1. Imagine a deck of 52 cards, ranging from twos through the face cards to aces, all in fo
mel-nik [20]

Answer:  A) 30 cards

<u>Step-by-step explanation:</u>

1. 52 cards

2. subtract red suit cards: 52 - 26 = 26

3. add back the hearts: 26 + 13 = 39

4. remove the 3 remaining jacks, 3 remaining queens, & 3 remaining kings:   39 - 9 = 30

There are 30 cards remaining

7 0
3 years ago
Find the indicated conditional probability
andrezito [222]

Given:

The two way table.

To find:

The conditional probability of P(Drive to school | Senior).

Solution:

The conditional probability is defined as:

P(A|B)=\dfrac{P(A\cap B)}{P(B)}

Using this formula, we get

P(\text{Drive to school }|\text{ Senior})=\dfrac{P(\text{Drive to school and senior})}{P(\text{Senior})}                      ...(i)

From the given two way table, we get

Drive to school and senior = 25

Senior = 25+5+5

           = 35

Total = 2+25+3+13+20+2+25+5+5

         = 100

Now,

P(\text{Drive to school and senior})=\dfrac{25}{100}

P(\text{Senior})=\dfrac{35}{100}

Substituting these values in (i), we get

P(\text{Drive to school }|\text{ Senior})=\dfrac{\dfrac{25}{100}}{\dfrac{35}{100}}

P(\text{Drive to school }|\text{ Senior})=\dfrac{25}{35}

P(\text{Drive to school }|\text{ Senior})=0.7142857

P(\text{Drive to school }|\text{ Senior})\approx 0.71

Therefore, the required conditional probability is 0.71.

5 0
3 years ago
Read 2 more answers
- 2y + 7y + 4<br> Can someone help
sladkih [1.3K]
Hi !
the answer is 5y+4

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6 0
3 years ago
Please help me with question
zhuklara [117]
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3 0
3 years ago
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Consider the graph of the linear function h(x) = –6 + h(x) equals negative 6 plus StartFraction 2 Over 3 EndFraction x. x. Which
kifflom [539]

The quadrant that the graph will not go through is the second quadrant.

The reason is that the slope is positive and there was a translation 6 units down

<h3>How to know the quadrant the graph will not pass</h3>

The quadrants are named in anticlockwise direction starting from the first which has x - positive and y - positive

The graph of y = 2x/3 is a graph with positive slope, moving through the third and first quadrant.

y = 2x/3 - 6 means a translation 6 units down and this pushed the line to get to the fourth quadrant

Hence the remaining quadrant that is untouched is the second quadrant

The graph is attached

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8 0
1 year ago
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