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Julli [10]
3 years ago
15

You are still debating about the two different computers. If you are paid $10.00/hour and your deductions are FICA (7.65%), fede

ral tax withholding (12%), and state tax withholding (8%), how many hours do you have to work to pay for the new computer?
Include step by step
Mathematics
1 answer:
sattari [20]3 years ago
8 0

Answer:

89 hours

Step-by-step explanation:

First solve all the deductions.

For each multiply the $10, which you are paid, and the percentage.

For FICA: $10 x 0.0765 = $0.77 per hr

For Fed tax: $10 x 0.12 = $1.2 per hr

For State tax: $10  x 0.08 = $0.8 per hr

Now subtract the remaining pay:

10 – 0.77 – 1.2 – 0.8 = $7.23

Time required = $640 / $7.23 per hr

Time required = 89 hrs

Final answer:

89 hours

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7 0
3 years ago
Li can walk 2 miles in 38 minutes. At that rate how far can she walk in 114 minutes?
mr Goodwill [35]

Answer:

114 minutes = 6 miles

Step-by-step explanation:

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4 0
2 years ago
Mrs. Galicia has a cupcake company. The amount of money earned is represented by
sashaice [31]

Using the profit function, it is found that:

a) She earns $36 after 25 years.

b) The function was shifted right 4 units and up 1 units.

<h3>What is the profit function?</h3>

The profit, in x years after 2015, is given by:

p(x) = 12\sqrt[3]{x + 2}

Item a:

She earns $36 after x years, considering x for which p(x) = 36, hence:

p(x) = 12\sqrt[3]{x + 2}

36 = 12\sqrt[3]{x + 2}

\sqrt[3]{x + 2} = 3

(\sqrt[3]{x + 2})^3 = 3^3

x + 2 = 27

x = 25

She earns $36 after 25 years.

Item b:

The new function is:

h(x) = 12\sqrt[3]{x - 2} + 1

At the domain, we have that x + 2 \rightarrow x - 2, that is, x \rightarrow x - 4, hence it was shifted right 4 units.

At the range, we have that h(x) = h(x - 4) + 1, hence it was shifted up 1 unit.

You can learn more about functions at brainly.com/question/24380382

6 0
2 years ago
Can someone awnser this 15 7x=105
masya89 [10]

Answer:

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5 0
3 years ago
What is the amplitude of the function
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Answer:

1

Step-by-step explanation:

Amplitude is the greatest distance from the mean line/mid line

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3 years ago
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