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3 years ago

The black graph is the graph of

Mathematics

1 answer:

alexdok [17]3 years ago

8 0

c.y+3=f(x) and 0+3 therefore x=3

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When a teacher divided her students into groups of four, she had three students remaining. when she divided them into groups of

AfilCa [17]

39 students....39/4 = 9 remainder 3
39/5 = 7 remainder 4

ur answer is 39

5 0

3 years ago

What is 8 7/9 − 3 2/3 =

maks197457 [2]

[|] Answer [|]

$\boxed{5 \ 1/9}$

[|] Explanation [|]

Rewrite the equation with parts separated:

8 + 7/9 - 3 - 2/3

Solve the whole number parts:

8 - 3 = 5

Solve the fraction parts:

7/9 - 2/3

Find LCD of 7/9 & 2/3

7/9 - 6/9 = 1/9

5 + 1/9 = 5 1/9

$\boxed{[|] \ Eclipsed \ [|]}$

4 0

3 years ago

3) The length of JM is 9x + 6 units, the length of JK is

Vlada [557]

Answer:

$JM = 60 units$

Step-by-step explanation:

Given:

$JM = 9x + 6$

$JK = 5x$

$KM = 3x + 12$

$JK + KM = JM$ (segment addition postulate)

$(5x) + (3x + 12) = (9x + 6)$ (substitution)

Solve for x

$5x + 3x + 12 = 9x + 6$

Collect like terms

$5x + 3x - 9x = -12 + 6$

$-x = -6$

Divide both sides by -1

$x = 6$

$JM = 9x + 6$

Plug in the value of x

$JM = 9(6) + 6$

$JM = 54 + 6$

$JM = 60 units$

3 0

3 years ago

Hasil dari 37²-√576:√144 adalah

valina [46]

Answer:

Answer is 1345:12

Step-by-step explanation:

${37 }^{2} - \sqrt{576} = {37}^{2} - 24 \\ = 1345 \\ {37}^{2} - \sqrt{576} : \sqrt{144} = 1345:12$

HAVE A NICE DAY!

THANKS FOR GIVING ME THE OPPORTUNITY TO ANSWER YOUR QUESTION. 

5 0

3 years ago

Find the median, lower quartile, and upper quartile for the set of data.

harkovskaia [24]

$\text{Find the median:}\\\\\text{To find the median, you would cross out the numbers from the side}\\\text{until you're left with the remainders. Put them in order and solve}\\\\1, 2, 4 ,5, 6, 7, 8, 9, 10, 11\\\text{Add 6 and 7 then divide by 2}\\\\6+7=13\\\\11\div2=6.5\\\\\boxed{\text{The median is 6.5}\\}\\\\\text{The lower quartile is the median of the numbers less than the median, so}\\\text{the numbers from 1-6}\\\\\text{When you cross out the numbers, you would be left with 4}$

$\boxed{\text{The lower quartile is 4}}\\\\\text{Do the same for the upper quartile for the numbers greater than half}\\\text{of the data set}\\\\\boxed{\text{Your upper quartile would be 9}}$

8 0

3 years ago

Read 2 more answers