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ser-zykov [4K]
3 years ago
7

The black graph is the graph of

Mathematics
1 answer:
alexdok [17]3 years ago
8 0

c.y+3=f(x) and 0+3 therefore x=3

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When a teacher divided her students into groups of four, she had three students remaining. when she divided them into groups of
AfilCa [17]
39 students....39/4 = 9 remainder 3
                       39/5 = 7 remainder 4

ur answer is 39
5 0
3 years ago
What is 8 7/9 − 3 2/3 =
maks197457 [2]

[|] Answer [|]

\boxed{5 \ 1/9}

[|] Explanation [|]

Rewrite the equation with parts separated:

8 + 7/9 - 3 - 2/3

Solve the whole number parts:

8 - 3 = 5

Solve the fraction parts:

7/9 - 2/3

Find LCD of 7/9 & 2/3

7/9 - 6/9 = 1/9

5 + 1/9 = 5 1/9

\boxed{[|] \ Eclipsed \ [|]}

4 0
3 years ago
3) The length of JM is 9x + 6 units, the length of JK is
Vlada [557]

Answer:

JM = 60 units

Step-by-step explanation:

Given:

JM = 9x + 6

JK = 5x

KM = 3x + 12

JK + KM = JM (segment addition postulate)

(5x) + (3x + 12) = (9x + 6) (substitution)

Solve for x

5x + 3x + 12 = 9x + 6

Collect like terms

5x + 3x - 9x = -12 + 6

-x = -6

Divide both sides by -1

x = 6

JM = 9x + 6

Plug in the value of x

JM = 9(6) + 6

JM = 54 + 6

JM = 60 units

3 0
3 years ago
Hasil dari 37²-√576:√144 adalah
valina [46]

Answer:

<em>Answer is</em><em> </em><em>1345</em><em>:</em><em>12</em>

Step-by-step explanation:

{37  }^{2}  -  \sqrt{576}  =  {37}^{2}  - 24 \\  = 1345 \\  {37}^{2}  -  \sqrt{576} : \sqrt{144}  = 1345:12

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

5 0
3 years ago
Find the median, lower quartile, and upper quartile for the set of data.
harkovskaia [24]

\text{Find the median:}\\\\\text{To find the median, you would cross out the numbers from the side}\\\text{until you're left with the remainders. Put them in order and solve}\\\\1, 2, 4 ,5, 6, 7, 8, 9, 10, 11\\\text{Add 6 and 7 then divide by 2}\\\\6+7=13\\\\11\div2=6.5\\\\\boxed{\text{The median is 6.5}\\}\\\\\text{The lower quartile is the median of the numbers less than the median, so}\\\text{the numbers from 1-6}\\\\\text{When you cross out the numbers, you would be left with 4}

\boxed{\text{The lower quartile is 4}}\\\\\text{Do the same for the upper quartile for the numbers greater than half}\\\text{of the data set}\\\\\boxed{\text{Your upper quartile would be 9}}

8 0
3 years ago
Read 2 more answers
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