The height that a ball reaches at a certain time t is given by the equation,
h = 2 - 15t + 5t²
We are asked to compute for the values of t that would allow the ball to reach a height of 7 meters.
Substitute the 7 to the equation,
7 = 2 - 15t + 5t²
Transposing,
5t² - 15t - 7 + 2 = 0
Simplifying,
5t² - 15t - 5 = 0
Divide the equation by 5,
t² - 3t - 1 = 0
The values of t can be calculated through the quadratic formula,
t = (-b +/- sqrt(b² - 4ac))/2a
Substituting,
t = (3 +/-sqrt (9 - 4(-1)) / 2(1)
t = 3.3 or t = -0.30
Since, we cannot have t as a negative number hence, our final answer is:
<em> t = 3.3 s</em>
I will have to assume that you actually meant " e^(ln 7x). The exponential and logarithmic functions are inverses of each other, so d^(ln 7x) = 7x (answer C).
Answer:
the quadrilateral is qrst then it is a parallelogram because two side of the diagonals
Answer:
x=9
Step-by-step explanation:
5( x + 7) - 3 ( x - 4) = 7x + 2
Distribute
5x+35 - 3x +12 = 7x +2
2x +47 = 7x+2
Subtract 2x from each side
2x+47-2x =7x -2x+2
47 = 5x+2
Subtract 2 from each side
47-2= 5x+2-2
45= 5x
Divide by 5
45/5 =5x/5
9 =x
Answer:
x=mc2 + 86
Step-by-step explanation:
