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3 years ago

PLEASE HELP ME WITH THIS

Mathematics

1 answer:

atroni [7]3 years ago

5 0

Answer:

the quadrilateral is qrst then it is a parallelogram because two side of the diagonals

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There are 604 students and teachers going on a field trip. A school bus holds 78 people. How many buses are needed for the field

Tasya [4]

Answer: 8 buses

Step-by-step explanation:

You need 8 buses minimum

8 0

3 years ago

Read 2 more answers

7. The startup cost for a boutique is $15,000, and each floral arrangement costs $17 for the boutique to make. If each arrangeme

Snowcat [4.5K]

Answer:

1875 arrangements

Step-by-step explanation:

Break-Even is the point when costs are equal to profit.

The cost is 15,000

We need to cover this up with the profit we get from sales.

Each arrangement is 17 (cost) and is sold for 25, so the profit from each arrangement is:

25 - 17 = 8

So, with each arrangement sale, we make profit of $8. How many of these we need to sell in order to break even (in order to make 15,000)??

We simply divide this amount (15,000) by the profit we make from each arrangement ($8), so that would be:

Number of Arrangements Needed to Break-Even = 15,000/8 = 1875

After 1875 arrangements, the boutique breaks even.

5 0

3 years ago

In a certain year, the population of Smallburg was 4,000. In the following year, the population increased by 15%. What was the r

kupik [55]

Answer:4600

Step-by-step explanation:

15% of 4000

15/100 x 4000

(15x4000) ➗ 100

60000 ➗ 100=600

4000+15% of 4000

4000+600=4600

8 0

3 years ago

Can someone please answer this correctly, I’ll reward points + brainalist

inessss [21]

Answer:

Step-by-step explanation:

median because it indicates the expected range of gas prices

4 0

3 years ago

Solve the quadratic equation<br> give your answer to 2 decimal places<br> : 3x^2+x-5=0

Dima020 [189]

Given:

The quadratic equation is:

$3x^2+x-5=0$

To find:

The solution for the given equation rounded to 2 decimal places.

Solution:

Quadratic formula: If a quadratic equation is $ax^2+bx+c=0$ , then:

$x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

We have,

$3x^2+x-5=0$

Here, $a=3,b=1,c=-5$ . Using the quadratic formula, we get

$x=\dfrac{-1\pm \sqrt{1^2-4(3)(-5)}}{2(3)}$

$x=\dfrac{-1\pm \sqrt{1+60}}{6}$

$x=\dfrac{-1\pm \sqrt{61}}{6}$

$x=\dfrac{-1\pm 7.81025}{6}$

Now,

$x=\dfrac{-1+7.81025}{6}$

$x=1.13504167$

$x\approx 1.14$

And

$x=\dfrac{-1-7.81025}{6}$

$x=-1.468375$

$x\approx -1.47$

Therefore, the required solutions are 1.14 and -1.47.

3 0

3 years ago