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charle [14.2K]
3 years ago
15

PLEASE HELP ME WITH THIS

Mathematics
1 answer:
atroni [7]3 years ago
5 0

Answer:

the quadrilateral is qrst then it is a parallelogram because two side of the diagonals

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A waiting room is 2/3 full when 36 people are seated. How many people are in the waiting room when it is 1/2 full?
Ahat [919]
When 36 people are seated the room is 2/3 full.
So for 1/3 , 18 people are needed
It will be 3/3 full if 54 people are present

So there can be 54 people in total

Now for the room to be 1/2 full , people will be 1/2 x 54 = 27 people
6 0
3 years ago
What is the product of 2•2
lisabon 2012 [21]

Answer:

4

Step-by-step explanation:

2*2 can be modeled using the following.

2 rows of 2

| |

| |

Total 4 sticks

7 0
2 years ago
Someone help me please?
jeka57 [31]

The Answer

LCD = 12

Equivalent Fractions with the LCD

2/3 = 8/12

3/4 = 9/12

1/2 = 6/12

Solution:

Rewriting input as fractions if necessary:

2/3, 3/4, 1/2

For the denominators (3, 4, 2) the least common multiple (LCM) is 12.

LCM(3, 4, 2)

Therefore, the least common denominator (LCD) is 12.

Calculations to rewrite the original inputs as equivalent fractions with the LCD:

2/3 = 2/3 × 4/4 = 8/12

3/4 = 3/4 × 3/3 = 9/12

1/2 = 1/2 × 6/6 = 6/12

Hope This Was Helpful :D

6 0
3 years ago
A = 1/2bh<br> b= 12<br> h = 7<br> how to I go about getting this answer?
Finger [1]
I know it is a triangle so 12×7=84÷2=42
4 0
3 years ago
In order to estimate the proportion of all likely voters who will likely vote for the incumbent in the upcoming city’s mayoral r
LekaFEV [45]

Answer:

Yes, there is evidence that more than 50% of likely voters will likely vote for the incumbent.

Step-by-step explanation:

We are given that in order to estimate the proportion of all likely voters who will likely vote for the incumbent in the upcoming city’s mayoral race, a random sample of 267 likely voters is taken, finding that 65% state they will likely vote for the incumbent.​

The polling agency wishes to test whether there is evidence that more than 50% of likely voters will likely vote for the incumbent.

<em>Let p = proportion of  voters who will likely vote for the incumbent</em>

SO, <u>Null Hypothesis</u>, H_0 : p \leq 50%   {means that less than or equal to 50% of likely voters will likely vote for the incumbent}

<u>Alternate Hypothesis</u>, H_A : p > 50%   {means that more than 50% of likely voters will likely vote for the incumbent}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

             T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where,  \hat p = sample proportion of voters who will likely vote for the incumbent in a sample of 267 voters = 65% or 0.65

            n = sample of voters = 267

So, <em><u>test statistics</u></em>  =   \frac{0.65-0.50}{{\sqrt{\frac{0.65(1-0.65)}{267} } } } }

                               =  5.139

<em>Since in the question we are not given the level of significance so we assume it to be 5%. Now at 0.05 significance level, the z table gives critical value of 1.6449 for right-tailed test. Since our test statistics is more than the critical value of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.</em>

Therefore, we conclude that the more than 50% of likely voters will likely vote for the incumbent. The strength of the evidence is 95%.

3 0
3 years ago
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