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RideAnS [48]
3 years ago
9

Midpoint of (2,4) to (8,2)

Mathematics
1 answer:
omeli [17]3 years ago
5 0

Answer:

midpoint of (2,4) and (2,8) is <u>( 5 , 3 )</u>

Step-by-step explanation:

your answer!

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If anyone knows about definite integrals for calculus then please I request help! I
kicyunya [14]

Answer:

\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:                                                           \displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Integration

  • Integrals

Integration Rule [Fundamental Theorem of Calculus 1]:                                     \displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)

Integration Property [Multiplied Constant]:                                                         \displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx

U-Substitution

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx

<u>Step 2: Integrate Pt. 1</u>

<em>Identify variables for u-substitution.</em>

  1. Set <em>u</em>:                                                                                                             \displaystyle u = 4x^{-2}
  2. [<em>u</em>] Differentiate [Basic Power Rule, Derivative Properties]:                       \displaystyle du = \frac{-8}{x^3} \ dx
  3. [Bounds] Switch:                                                                                           \displaystyle \left \{ {{x = 9 ,\ u = 4(9)^{-2} = \frac{4}{81}} \atop {x = 5 ,\ u = 4(5)^{-2} = \frac{4}{25}}} \right.

<u>Step 3: Integrate Pt. 2</u>

  1. [Integral] Rewrite [Integration Property - Multiplied Constant]:                 \displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^9_5 {\frac{-8}{x^3}e^\big{4x^{-2}}} \, dx
  2. [Integral] U-Substitution:                                                                              \displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^{\frac{4}{81}}_{\frac{4}{25}} {e^\big{u}} \, du
  3. [Integral] Exponential Integration:                                                               \displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}(e^\big{u}) \bigg| \limits^{\frac{4}{81}}_{\frac{4}{25}}
  4. Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]:           \displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8} \bigg( e^\Big{\frac{4}{81}} - e^\Big{\frac{4}{25}} \bigg)
  5. Simplify:                                                                                                         \displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

4 0
3 years ago
Which unit would be best for measuring the thickness of a coin
choli [55]

Answer: Milimeters (mm)

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
Are the following figures similar? Rectangles ABCD and EFGH are shown. AB equals 5. BC equals 25. EF equals 3. FG equals 15. Yes
Tatiana [17]

Answer:

Yes; the corresponding sides are proportional

Step-by-step explanation:

If two figures are similar, the lengths of their sides are proportional.  This means if we set up a proportion with the sides we are given and cross-multiply, we get a true statement at the end of it.

Using the similarity statement ABCD~EFGH, we will compare AB to EF and BC to FG:

5/3 = 25/15

Cross multiply:

5(15) = 3(25)

75 = 75

We got a true statement, so the sides are proportional.

8 0
3 years ago
Read 2 more answers
45% as fraction in the simplest form​
Kobotan [32]

Answer:9/20

Step-by-step explanation: 45/100=9/20, 45÷5=9, 100÷5=20 both the denominater and the numerator are divisible by 5.

7 0
3 years ago
Read 2 more answers
Which transformations can be used to carry ABCD onto itself? The point of
dmitriy555 [2]

Answer:

A and B

Step-by-step explanation:

For A, y=2 is the axis of vertical symmetry, meaning a reflection would map the shape onto itself.

For B, x=3 is the axis of horizontal symmetry, meaning a reflection would map the shape onto itself.

For C, a rotation of 90 degrees would make the shape taller vertically and shorter horizontally, therefore it would be wrong.

For D, a translation two units down would move all points down, even though some would need to go up, therefore it would be wrong.

7 0
3 years ago
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