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victus00 [196]
2 years ago
10

A piece of wood is cut into three different sized pieces. The ratio of the three pieces is 4:5:6. If the actual length of the wo

od is 45 inches, then what is the length of the short side?

Mathematics
2 answers:
vekshin12 years ago
8 0

Answer:

Step-by-step explanation:

This is a question worth knowing how to do. It is prime candidate for a test question.

Equation

Let the unit be x

therefore

4x + 5x + 6x = 45

Solution

15x = 45

x = 45/15

x = 3

The shortest piece is 4*3 = 12

The middle piece = 5*3   = 15

The longest piece = 6*3 = 18

Total                                    45

artcher [175]2 years ago
4 0

Answer:

12

Step-by-step explanation:

So 4:5:6 = 45

4+5+6 = 15

45/15 = 3

Since 4 is the smallest, 4*3 = 12.

Hope this works!

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A piece of wire 23 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria
AURORKA [14]

Answer:

For maximum area, all of the wire should be used to construct the square.

The minimum total area is obtained when length of the wire is 10m

Step-by-step explanation:

For maximum,  we use the whole length

For minimum,

supposed the x length was used for the square,

the length of the side of the square = x/4m

Area = \frac{x^{2} }{16}

For the equilateral triangle, the length of the side =  \frac{23 - x}{3}

Area = \frac{\sqrt{3} }{4}  a^{2}  = \frac{\sqrt{3} }{4} (\frac{23 - x}{3} )^{2}

Total Area = \frac{x^{2} }{16}  + \frac{\sqrt{3} }{36} (23-x)^{2}

\frac{dA}{dx}  = \frac{x}{8}  -  \frac{\sqrt{3} }{18} (23 - x)\\

\frac{d^{2}A }{dx^{2} }  = \frac{1}{8}  + \frac{\sqrt{3} }{18}  > 0, therefore it is minimum

\frac{dA}{dx}  = 0 \\\\

\frac{x}{8}  -  \frac{\sqrt{3} }{18} (23 - x) = 0\\

x = 10.00m

3 0
3 years ago
Read 2 more answers
Given vectors u = (−1, 2, 3) and v = (3, 4, 2) in R 3 , consider the linear span: Span{u, v} := {αu + βv: α, β ∈ R}. Are the vec
julia-pushkina [17]

Answer:

(2,6,6) \not \in \text{Span}(u,v)

(-9,-2,5)\in \text{Span}(u,v)

Step-by-step explanation:

Let b=(b_1,b_2,b_3) \in \mathbb{R}^3. We have that b\in \text{Span}\{u,v\} if and only if we can find scalars \alpha,\beta \in \mathbb{R} such that \alpha u + \beta v = b. This can be translated to the following equations:

1. -\alpha + 3 \beta = b_1

2.2\alpha+4 \beta = b_2

3. 3 \alpha +2 \beta = b_3

Which is a system of 3 equations a 2 variables. We can take two of this equations, find the solutions for \alpha,\beta and check if the third equationd is fulfilled.

Case (2,6,6)

Using equations 1 and 2 we get

-\alpha + 3 \beta = 2

2\alpha+4 \beta = 6

whose unique solutions are \alpha =1 = \beta, but note that for this values, the third equation doesn't hold (3+2 = 5 \neq 6). So this vector is not in the generated space of u and v.

Case (-9,-2,5)

Using equations 1 and 2 we get

-\alpha + 3 \beta = -9

2\alpha+4 \beta = -2

whose unique solutions are \alpha=3, \beta=-2. Note that in this case, the third equation holds, since 3(3)+2(-2)=5. So this vector is in the generated space of u and v.

4 0
2 years ago
If you roll a six-sided die, what is the probability that you will roll a 3?
Lana71 [14]

Answer:

the probability is 1/6, or 16.6%

7 0
3 years ago
Find one solution for the equation. Assume that all angles involved are acute angles. tangent (3 Upper B minus 32 degrees )equal
raketka [301]

Answer:

Step-by-step explanation:

Equation given

tan(3B-32 ) = cot ( 5B +10 ) = tan [ 90 - ( 5B + 10 ) ]

tan(3B-32 ) = tan  (90 - 5B - 10 )

(3B-32 ) =  (90 - 5B - 10 )

8B = 32 + 80

B = 14° .

5 0
2 years ago
I need help with this question fast! i don't have a lot of time! can someone help me please???
jarptica [38.1K]
16x^4-81y^4  difference of perfect squares...

(4x^2-9y^2)(4x^2+9y^2)  that's one of the equivalents...

(2x+3y)(2x-3y)(4x^2+9y^2)  that's another one of them...
5 0
3 years ago
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