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andrew-mc [135]
3 years ago
5

Mark rolls a fair dice 36 times. How many times would Mark expect to roll a number greater than 5?​

Mathematics
2 answers:
DochEvi [55]3 years ago
4 0

Answer:

Let X be the number of times a Dice rolls 4.

Expected value is 96/6 = 16.

Step-by-step explanation:

exis [7]3 years ago
3 0

Answer:

6

Step-by-step explanation:

In a dice, there are 6 faces, there's {1, 2, 3, 4, 5, 6}.

So when the question asks a number greater than 5 it means that it wants the "6". The probability to get the "6" is 1/6. So to find the expected value you just times the number of rolls with the probability which means 36 × 1/6 which equals to 6 times

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Answer:

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A= 20000(1+\frac{0.077}{24} )^2^*^2^4\\\\A= 20000(1+0.003 )^2^*^2^4\\\\A= 20000(1.003 )^2^*^2^4\\\A= 20000(1.003 )^4^8\\\A= 20000*1.15463517818\\\A= 23092.7035636\\\A= 23,092.70

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