All categories

3 years ago

Indicate the method you would use to prove the triangles congruent. If no

Mathematics

1 answer:

babunello [35]3 years ago

6 0

Step-by-step explanation:

I suspect we don't see the full information for the problem here.

all listed 3 methods are typically used to prove that triangles are congruent (= when turned to have the same orientation, they would simply cover each other completely - no overhanging parts from either triangle).

I guess there is a diagram with 2 triangles and what is known about them.

and since we cannot see them, we cannot tell you which method would apply here.

just remember

SSS means all 3 sides of one triangle are exactly the same as the 3 sides of the other triangle. if you know the lengths of all 3 sides, there is only one triangle you can create. you can only orient it differently.

SAS means two sides and the enclosed angle are the same. again, only one triangle can be created with that information.

ASA means one side and the 2 angles at the end points of that side are known. again, only one triangle can be created with that information.

You might be interested in

The hypotenuse of a right triangle has length 50 cm. One leg has length 20 cm. The nearest tenth, what is the length of the othe

Fantom [35]

Answer:

45.8 cm

Step-by-step explanation:

Let the length of other leg be l

By pythagoras theorem,

$l \: = \sqrt{ {50}^{2} - {20}^{2} } \\ l \: = 45.8cm$

6 0

3 years ago

Find the volume of each figure round to the near tenth only number 2 pls it’s 20 points

Nana76 [90]

Answer:

2094.4yds cubed

Step-by-step explanation:

V=pi*r^2*h/3

V=pi*100*20/3

V≈2094.4

6 0

3 years ago

The functions q and r are defined as follows.

UkoKoshka [18]

Q(3) = -2(3)+2 = -4
r(q(3)) = (-4)^2-1 = 15

3 0

3 years ago

1.) Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth .x squared minus 21 x equals n

Andrew [12]

Part 1
We are given $x^2-21x=-4x$ . This can be rewritten as $x^2-18x=0$ .
Therefore, a=1, b=-18, c=0.
Using the quadratic formula
$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}=\frac{-\left(-18\right)\pm \sqrt{\left(-18\right)^2-4\left(1\right)\left(0\right)}}{2\left(1\right)}$
$x=\frac{18\pm 18}{2}$

The values of x are
$x_1=\frac{18-18}{2}=0$
$x_2=\frac{18+18}{2}=18$

Part 2
Since the values of y change drastically for every equal interval of x, the function cannot be linear. Therefore, the kind of function that best suits the given pairs is a quadratic function.

Part 3.
The first equation is $y=x^2+2$ .
The second equation is $y=3x+20$ .

We have
$x^2+2=3x+20$
$x^2-3x-18=0$
Factoring, we have
$\left(x-6\right)\left(x+3\right)=0$
Equating both factors to zero.
$x_1-6=0\rightarrow x_1=6$
$x_2+3=0\rightarrow x_2=-3$

When the value of x is 6, the value of y is
$y=3\left(6\right)+20=38$

When the value of x is -3, the value of y is
$y=3\left(-3\right)+20=11$

Therefore, the solutions are (6,38) or (-3,11)

7 0

3 years ago

Give the appropriate theorem or postulate that can

vitfil [10]

Answer:

The right answer is A. AA Postulate

4 0

2 years ago