Please help due in less than 3 hours!!!!!!!! When Anne biked down the canyon, she averaged 30 miles per hour. At this rate, how
2 answers:
Answer:
It took Anne 1/30 of an hour to bike 1 mile.
Step-by-step explanation:
Unit Rate - 30 miles/ 1 hour
Based on the visual above, we need to find the proportion.
30 miles divided 30 equals to 1 mile.
What is 1 hour divided by 30? Remember: <u>whatever is done to the numerator must be done to the denominator</u>!
1 divided by 30 equals 1/30. Since the unit is hour, the answer is 1/30 <em>of</em> an hour.
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Answer:
- 160 ft (out from the river)
- 320 ft (parallel to the river)
Step-by-step explanation:
Let x represent the length of fence parallel to the river. Then the dimension of perpendicular to the river will be half the remaining fence: (640-x)/2. The total area will be ...
A = x(640-x)/2
This is the equation of a parabola that opens downward. It has zeros at x=0 and x=640, so its axis of symmetry is x = (0+640)/2 = 320. That is, the peak of the area curve is found when x=320.
The dimensions of the garden with the largest area are 160 ft wide by 320 ft long, where the long side is the river side.
Remark
If you don't start exactly the right way, you can get into all kinds of trouble. This is just one of those cases. I think the best way to start is to divide both terms by x^(1/2)
Step One
Divide both terms in the numerator by x^(1/2)
y= 6x^(1/2) + 3x^(5/2 - 1/2)
y =6x^(1/2) + 3x^(4/2)
y = 6x^(1/2) + 3x^2 Now differentiate that. It should be much easier.
Step Two
Differentiate the y in the last step.
y' = 6(1/2) x^(- 1/2) + 3*2 x^(2 - 1)
y' = 3x^(-1/2) + 6x I wonder if there's anything else you can do to this. If there is, I don't see it.
I suppose this is possible.
y' = 3/x^(1/2) + 6x
y' =
Frankly I like the first answer better, but you have a choice of both.
If you don't start exactly the right way, you can get into all kinds of trouble. This is just one of those cases. I think the best way to start is to divide both terms by x^(1/2)
Step One
Divide both terms in the numerator by x^(1/2)
y= 6x^(1/2) + 3x^(5/2 - 1/2)
y =6x^(1/2) + 3x^(4/2)
y = 6x^(1/2) + 3x^2 Now differentiate that. It should be much easier.
Step Two
Differentiate the y in the last step.
y' = 6(1/2) x^(- 1/2) + 3*2 x^(2 - 1)
y' = 3x^(-1/2) + 6x I wonder if there's anything else you can do to this. If there is, I don't see it.
I suppose this is possible.
y' = 3/x^(1/2) + 6x
y' =
Frankly I like the first answer better, but you have a choice of both.