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3 years ago

14

A factory inspector found flaws in 3 out of 18 wooden boxes what is the experimental probability that the next wooden box will b

e flawed

1 answer:

Sphinxa [80]3 years ago

7 0

Answer:

16.666% would be flawed.

Step-by-step explanation:

You might be interested in

with the exception of the first house, all the houses on sequence lane have an address whose numerical portions are greater than

yanalaym [24]

Answer:

The address of Ainsley is 24 and that of Lane is 25.

Step-by-step explanation:

All the houses on sequence lane have an address whose numerical portions are greater than that of the prior house.

Now, if Ainsley and Lane are next-door neighbors and the sum of the numerical portions of their addresses is 49.

Let the Ainsley has the address with numeric portion x, then Lane has the address with numeric portion x + 1.

Therefore, x + (x + 1) = 49

⇒ 2x = 48

⇒ x = 24

So, the address of Ainsley is 24 and that of Lane is 25. (Answer)

4 0

3 years ago

Simplify the following expression: (1 point) 2x − 2y + 5z − 2x − y + 3z

Karo-lina-s [1.5K]

Answer: -3y + 8z

Step-by-step explanation:

2x -2x = 0

-2y + - y= -3y

5z + 3z= 8z

-3y + 8z

4 0

3 years ago

Read 2 more answers

A fruit stand sells 6 oranges for $3 and 3 grape fruit for $2.40 .Lionel buys 10 oranges and 11 grapefruits. how much does Lione

Flura [38]

6oragnes=3dollars
divide 6
1oragne=0.5dollar

3grapefruit=2.4dollar
divide3
1grapefruit=0.6dollar

10 oranges and 11 grapefuites
(10 times 0.5)+(11 times 0.6) =
5+6.6=11.6

answer is $11.6

8 0

3 years ago

Read 2 more answers

lutik1710 [3]

Answer:

<u>c = 10 - 11(0.65)</u>

Step-by-step explanation:

The equation is :

<u>c = 10 - 11(0.65)</u>

<u />

Change will be :

c = 10 - 7.15
c = $2.85

5 0

2 years ago

Read 2 more answers

A tire company finds that the lifespan for one brand of its tires is normally distributed with a mean of 47,500 miles and a stan

Illusion [34]

Answer:

42580 miles

Step-by-step explanation:

Mean = $\mu = 47500$

$\sigma = 3000$

The manufacturer does not want to replace more than 5% of the tires

$P(X\leq x)=5\%$

$P(\frac{x-\mu}{\sigma}\leq \frac{x-47500}{3000})=0.05$

By using normal table values :

$\frac{x-47500}{3000}=-1.64$

$x=(-1.64 \times 3000)+47500$

$x=42580$

Hence the approximate number of miles for the warranty is 42580 miles

6 0

3 years ago