Answer:
c
Step-by-step explanation:
AD || BC and BD is the transversal,
Therefore, angle DBC = angle ADB = 42° [alternate angles]
AD || BC and BD is the transversal,
angle BAD + angle ABD + angle DBC = 180° [co-interior angles]
or, 106°+ angle ABD + 42° = 180°
or, 148° + angle ABD = 180°
or, angle ABD = 180°-148° = 32°
Therefore, angle ABC = (32+42)° = 74°
AB||CD and BC is the transversal,
angle ABC + angle BCD = 180° [co-interior angles]
or, 72+2x+12 = 180
or, 84+2x = 180
or, 2x=180-84 = 96
or, x = 48
Answers: a)48°
b)42°
c)72°
If I understand what you are asking, you can use the median as an average since it is not affected by the mean ( median is a measure of center). Since a mean is affected by outliers, it might lower the score if there are very low outliers. But note that if there are outliers way <em>greater </em>it can increase the average. You can use the Inter Quartile Range if shown on a box plot ( measure of variability).
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Answer:
Step-by-step explanation:
- -11/2+27/4+(-17/4)
- (-22+27-17)/4
- (-12)/4
- -3
