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weqwewe [10]
3 years ago
9

Using the Pythagorean Theorem, find the distance between the points.

Mathematics
1 answer:
Paha777 [63]3 years ago
4 0

Answer:

(5,7,8.6)

Step-by-step explanation:

Create a line on each the x axis and the y axis which intersects at a right triangle. The x axis line is 7 squares and the y axis is 5 squares. Now you can use the Pythagorean theorem.

a^2+b^2=c^2

7^2+5^2=c^2

49+25=c^2

74=c^2

8.6=c

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Answer:

Step-by-step explanation:

First, you should put the axis of symetry as 5, -7 because f(x)= (x-h)^2+k and h is 5 and k is -7. the axis of symetry is x=5 because that is the "folding point" of the graph. Next, you would have to plug In 4 and 6 as your helping points to tell you where the other points of the function are going to be.

Plug 4 in and you get -6. plug 6 in and you get -6. plot the points (4, -6) and (6,-6).

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Read 2 more answers
The function C(L) = |L – 105| can be used to determine the difference between the expected and actual crop of lemons, L, from a
REY [17]

Answer:

w(C(L))= 0.25 |L - 105|

Step-by-step explanation:

you plug in C(L) into  L in w(L)

7 0
3 years ago
You are creating an open top box with a piece of cardboard that is 16 x 30“. What size of square should be cut out of each corne
Arada [10]

Answer:

\frac{10}{3} \ inches of square should be cut out of each corner to create a box with the largest volume.

Step-by-step explanation:

Given: Dimension of cardboard= 16 x 30“.

As per the dimension given, we know Lenght is 30 inches and width is 16 inches. Also the cardboard has 4 corners which should be cut out.

Lets assume the cut out size of each corner be "x".

∴ Size of cardboard after 4 corner will be cut out is:

Length (l)= 30-2x

Width (w)= 16-2x

Height (h)= x

Now, finding the volume of box after 4 corner been cut out.

Formula; Volume (v)= l\times w\times h

Volume(v)= (30-2x)\times (16-2x)\times x

Using distributive property of multiplication

⇒ Volume(v)= 4x^{3} -92x^{2} +480x

Next using differentiative method to find box largest volume, we will have \frac{dv}{dx}= 0

\frac{d (4x^{3} -92x^{2} +480x)}{dx} = \frac{dv}{dx}

Differentiating the value

⇒\frac{dv}{dx} = 12x^{2} -184x+480

taking out 12 as common in the equation and subtituting the value.

⇒ 0= 12(x^{2} -\frac{46x}{3} +40)

solving quadratic equation inside the parenthesis.

⇒12(x^{2} -12x-\frac{10x}{x} +40)=0

Dividing 12 on both side

⇒[x(x-12)-\frac{10}{3} (x-12)]= 0

We can again take common as (x-12).

⇒ x(x-12)[x-\frac{10}{3} ]=0

∴(x-\frac{10}{3} ) (x-12)= 0

We have two value for x, which is 12 and \frac{10}{3}

12 is invalid as, w= (16-2x)= 16-2\times 12

∴ 24 inches can not be cut out of 16 inches width.

Hence, the cut out size from cardboard is \frac{10}{3}\ inches

Now, subtituting the value of x to find volume of the box.

Volume(v)= (30-2x)\times (16-2x)\times x

⇒ Volume(v)= (30-2\times \frac{10}{3} )\times (16-2\times \frac{10}{3})\times \frac{10}{3}

⇒ Volume(v)= (30-\frac{20}{3} ) (16-\frac{20}{3}) (\frac{10}{3} )

∴  Volume(v)= 725.93 inches³

6 0
3 years ago
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