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Novosadov [1.4K]
3 years ago
10

Evaluate −2(2/5)^10x for x=1/5.

Mathematics
1 answer:
kenny6666 [7]3 years ago
8 0

Answer:

-8/25

Step-by-step explanation:

I took the test and i got it right

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Solve the following inequality: 3-5x-x^2>=0
Dennis_Churaev [7]

Answer:

-5/2+-1/2√37≤x≤-5/2+1/2√37

Step-by-step explanation:

Step 1: Find the critical points

-x^2-5x+3=0

For this equation: a=-1, b=-5, c=3

−1x^2+−5x+3=0

x=−b±√b2−4ac/2a

x=−(−5)±√(−5)2−4(−1)(3)/2(-1)

x=5±√37 /−2

x=-5/2+1/2√37

Step 2: Check intervals in between critical points

x≤-5/2+1/2 √37 (Doesn't work in original inequality)

-5/2+-1/2√37≤x≤-5/2+1/2√37 (Works in original inequality)

x≥-5/2+1/2 √37 (Doesn't work in original inequality)

5 0
3 years ago
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