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Ivanshal [37]
3 years ago
5

Question 1 (Multiple Choice Worth 4 points)

Mathematics
1 answer:
VLD [36.1K]3 years ago
4 0

Answer:

In the first expression:

(5^3)^-4 = 5^-12

Step-by-step explanation:

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Determine the value of a + b in the system of equations below. <br><br> 5a + 4b = 22<br> 7a-b= 11
dexar [7]

Answer:

We have a + b as;

2 + 3 = 5

Step-by-step explanation:

Here, we want go get the value of a and b

from the second equation, we can get an expression for b

We have this as;

7a - b = 11

Thus,

b = 7a - 11

Now, from here, we can substitute the value of b into the first equation

We have this as;

5a + 4(7a - 11) = 22

5a + 28a -44 = 22

33a = 22 + 44

33a = 66

a = 66/33

a = 2

Recall;

b = 7a - 11

substituting the value of a from above;

b = 7(2) - 11

b = 14 - 11

b = 3

6 0
3 years ago
Which triangles are similar?
lara31 [8.8K]
I’m pretty sure it would be a and b
3 0
3 years ago
Complete the equation of the line through (-6,-5) (−4,−4) PLZ HELP !!!
bogdanovich [222]

Answer: y=1/2x−2

Step-by-step explanation:

6 0
3 years ago
there are quite a bit of them but i just need someone to convert these fractions to decimals....thanks&lt;3
Mariana [72]

Answer:

1/9=0.111111111 2/9=0.222222222 3/9=0.333333333 4/9=0.444444444

5/9=0.555555556 6/9=0.666666667 7/9=0.777777778 8/9=0.888888889

Step-by-step explanation:

sorry i dont have time to do them all but heres all of the nines

4 0
3 years ago
Let A= {a,b,c,d,e} and let B= {1,2,3,4,5} determine n(AxB)
777dan777 [17]

n(AxB) = 25

Step-by-step explanation:

AxB in sets is called Cartesian product. And is defined as a set of ordered pairs (a,b) where a belongs to A and b belongs to B.

Given

A = {a,b,c,d,e}

B = {1,2,3,4,5}

The number of elements for Cartesian product of two sets is determined by:

n(AxB) = n(A) * n(B)

Here

n(A) = 5\\n(B) = 5

So,

n(AxB) = 5*5 = 25

Hence,

n(AxB) = 25

Keywords: Sets, Cartesian Product

Learn more about sets at:

  • brainly.com/question/5102020
  • brainly.com/question/5147732

#LearnwithBrainly

7 0
3 years ago
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