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il63 [147K]
2 years ago
11

The number of dogs at the animal shelter is 150 less than the number of

Mathematics
1 answer:
Hoochie [10]2 years ago
6 0

Answer:

48, hope this helps!

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En un triángulo rectángulo A es un ángulo agudo y Sen A = 4/5 ¿Cuál será el valor de Tan A?
Nonamiya [84]

Answer:

\displaystyle \tan A=\frac{4}{3}

Step-by-step explanation:

<u>Funciones Trigonométricas</u>

La identidad principal en trigonometría es:

sen^2A+cos^2A=1

Si sabemos que A es un ángulo agudo (que mide menos de 90°), su seno y coseno son positivos.

Dado que Sen A = 4/5, calculamos el coseno:

cos^2A=1-sen^2A

Sustituyendo:

\displaystyle cos^2A=1-\left(\frac{4}{5}\right)^2

\displaystyle cos^2A=1-\frac{16}{25}

\displaystyle cos^2A=\frac{25-16}{25}

\displaystyle cos^2A=\frac{9}{25}

Tomando raíz cuadrada:

\displaystyle cos\ A=\sqrt{\frac{9}{25}}=\frac{3}{5}

La tangente se define como:

\displaystyle \tan A=\frac{sen\ A}{cos\ A}

Substituyendo:

\displaystyle \tan A=\frac{\frac{4}{5}}{\frac{3}{5}}

\displaystyle \tan A=\frac{4}{3}

6 0
3 years ago
2 dots plots with number lines going from 0 to 10. Plot A has 0 dots above 0, 1, and 2, 1 above 3, 2 above 4, 2 above 5, 2 above
alexandr402 [8]

Answer:

First one:

Both the mean and median are greater for Plot A than for Plot B

Step-by-step explanation:

Set A:

Mean:

[1×10 + 2×7 + 2×6 + 2×5 + 2×4 + 1×3]/10

= 5.7

Median:

Median position: (10+1)/2 = 5.5th value

(5+6)/2

Median = 5.5

Set B:

Mean:

[1×7 + 3×6 + 3×5 + 2×4 + 1×3]/10

= 5.1

Median:

Median position: (10+1)/2 = 5.5th value

(5+5)/2

Median = 5

Mean: A is greater

Median: A is greater

8 0
3 years ago
Which equation best represents the line of best fit for the scatterplot?
Elena L [17]

Answer:

The answer for this problem is

C) y = -x + 6

Step-by-step explanation:

I know this because I just did the test

5 0
3 years ago
Identify one characteristic of exponential growth.
vodka [1.7K]
If I were u I would chose B
7 0
2 years ago
Help i have math homework and im real bad at it i got a B- last year so help
Natalka [10]
4y-12 is the answer
7 0
2 years ago
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