Answer:
Include as much detail on slides as you have room for.
Explanation:
It contradicts some of the other points, if you add too much the slide will look overcrowded and be hard to read.
The option that is true for the Student Version above is option d: This is not plagiarism.
<h3>What is
plagiarism?</h3>
This is known to be the act of copying other people's work and then taking it as your own.
When you look at the student work, you will see some measures od differences. Hence, The option that is true for the Student Version above is option d: This is not plagiarism.
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See full question below
Original Source Material
There is a design methodology called rapid prototyping, which has been used successfully in software engineering. Given similarities between software design and instructional design, we argue that rapid prototyping is a viable method for instructional design, especially for computer-based instruction.
Student Version
Rapid prototyping could be an advantageous methodology for developing innovative computer-based instruction. Software engineers have been successful in designing applications by using rapid prototyping. So it also could be an efficient way to do instructional design.
Which of the following is true for the Student Version above?
a. Word-for-Word plagiarism
b. Paraphrasing plagiarism
c. This is not plagiarism
Answer:
I, II, and III
Explanation:
The three are almost saying the same thing. the loop is one am a bit concerned about. but since the oddnum is set to false, the loop will work.
The one and two are pretty clear. to test for odd number, the easiest is to divide by two to see if there will be a remainder. That is what both first and second statement is trying to do.
Answer:
#include <iostream>
using namespace std;
int main()
{
int factorial=1;
int num;
cout<<"Enter any Number: ";
cin>>num;
for(int i=1;i<=num;i++){
factorial=factorial * i;
}
cout<<"The factorial of the number is "<<factorial<<endl;
return 0;
}
Explanation:
Create the main function and declare the variable.
then, print the message by using the cout instruction.
store the value enter by user in the variable.
After that, take a for loop from 1 to user value both are included.
and multiply the value with previous value and it happen until the condition in the loop true.
for example:
i=1
fact = 1*1=1
i=2
fact = 1*2=2
i=3
fact= 2*3=6 and so on....
finally print the result.
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