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Yakvenalex [24]
4 years ago
5

What is an electronic tool that stores large amounts of data in one place in a systematic, logical way? A Database B Platform C

Query D Software
Computers and Technology
1 answer:
ohaa [14]4 years ago
4 0

Answer:

Database: An integrated collection of logically related records or files. A database consolidates records previously stored in separate files into a common pool of data records that provides data for many applications. The data is managed by systems software called database management systems (DBMS). The data stored in a database is independent of the application programs using it and of the types of secondary storage devices on which it is stored.

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Implement a method called bubbleSort, that takes an ArrayList, sorts it using bubble sort algorithm, and returns a sorted list;
boyakko [2]

Answer:

Java algorithm is given below

Explanation:

import java.util.ArrayList;

import java.util.Arrays;

import java.util.Random;

public class Temp {

   static void bubbleSort(ArrayList<Integer> list) {

       int n = list.size();

       for (int p = 0; p < n - 1; p++)

           for (int q = 0; q < n - p - 1; q++)

               if (list.get(q) > list.get(q + 1)) {

                   int temp = list.get(q);

                   list.set(q, list.get(q + 1));

                   list.set(q + 1, temp);

               }

   }

   static void selectionSort(ArrayList<Integer> list) {

       int n = list.size();

       for (int p = 0; p < n - 1; p++) {

           int minimumIndex = p;

           for (int q = p + 1; q < n; q++)

               if (list.get(q) < list.get(minimumIndex))

                   minimumIndex = q;

           int temp = list.get(p);

           list.set(p, list.get(minimumIndex));

           list.set(minimumIndex, temp);

       }

   }

   static void insertionSort(ArrayList<Integer> list) {

       int size = list.size();

       int p, val, q;

       for (p = 1; p < size; p++) {

           val = list.get(p);

           q = p - 1;

           while (q >= 0 && list.get(q) > val) {

               list.set(q + 1, list.get(q));

               q = q - 1;

           }

           list.set(q + 1, val);

       }

   }

   static void mergeSort(ArrayList<Integer> list, int low, int high) {

       if (low < high && (high - low) >= 1) {

           int mid = (high + low) / 2;

           mergeSort(list, low, mid);

           mergeSort(list, mid + 1, high);

           merger(list, low, mid, high);

       }

   }

   static void merger(ArrayList<Integer> list, int low, int mid, int high) {

       ArrayList<Integer> mergedArray = new ArrayList<Integer>();

       int left = low;

       int right = mid + 1;

       while (left <= mid && right <= high) {

           if (list.get(left) <= list.get(right)) {

               mergedArray.add(list.get(left));

               left++;

           } else {

               mergedArray.add(list.get(right));

               right++;

           }

       }

       while (left <= mid) {

           mergedArray.add(list.get(left));

           left++;

       }

       while (right <= high) {

           mergedArray.add(list.get(right));

           right++;

       }

       int i = 0;

       int j = low;

       while (i < mergedArray.size()) {

           list.set(j, mergedArray.get(i++));

           j++;

       }

   }

   public static void main(String[] args) throws Exception {

       ArrayList<Integer> list = new ArrayList<>();

       Random rand = new Random(System.currentTimeMillis());

       for (int i = 0; i < 10000; i++) {

           list.add(rand.nextInt(256));

       }

       long start = System.currentTimeMillis();

       selectionSort(list);

       int sel = (int) (System.currentTimeMillis() - start);

       System.out.println("Selection Sort time (in ms): " + sel);

       list.clear();

       // ------------------------

       rand = new Random(System.currentTimeMillis());

       for (int i = 0; i < 10000; i++) {

           list.add(rand.nextInt(256));

       }

       start = System.currentTimeMillis();

       insertionSort(list);

       int ins = (int) (System.currentTimeMillis() - start);

       System.out.println("Insertion Sort time (in ms): " + ins);

       list.clear();

       // ------------------------

       rand = new Random(System.currentTimeMillis());

       for (int i = 0; i < 10000; i++) {

           list.add(rand.nextInt(256));

       }

       start = System.currentTimeMillis();

       bubbleSort(list);

       int bub = (int) (System.currentTimeMillis() - start);

       System.out.println("Bubble Sort time (in ms): " + bub);

       list.clear();

       // ---------------------------

       rand = new Random(System.currentTimeMillis());

       for (int i = 0; i < 10000; i++) {

           list.add(rand.nextInt(256));

       }

       start = System.currentTimeMillis();

       mergeSort(list, 0, list.size() - 1);

       int mer = (int) (System.currentTimeMillis() - start);

       System.out.println("Merge Sort time (in ms): " + mer);

       long m = Math.min(Math.min(sel, ins), Math.min(bub, mer));

       if (m == sel)

           System.out.println("Selection Sort is fastest");

       else if (m == ins)

           System.out.println("insertion Sort is fastest");

       else if (mer == m)

           System.out.println("Merge Sort is fastest");

       else if (m == bub)

           System.out.println("Bubble Sort is fastest");

   }

}

6 0
3 years ago
Please help me with computing!
Sladkaya [172]

Answer:

ok i help

Explanation:

3 0
3 years ago
Write a program that reads the contents of the two files into two separate lists. The user should be able to enter a boy’s name,
insens350 [35]

Answer:

Check Explanation.

Explanation:

A programming language is used by engineers, technologists, scientists or someone that learnt about programming languages and they use these programming languages to give instructions to a system. There are many types for instance, c++, python, Java and many more.

So, the solution to the question above is given below;

#define the lists

boyNames=[]

girlNames=[]

#open the text file BoyNames.txt

with open('BoyNames.txt','r') as rd_b_fl:

boyNames=rd_b_fl.readlines()

boyNames=[name.strip().lower() for name in boyNames]

#open the text file GirlNames.txt

with open('GirlNames.txt','r') as rd_b_fl:

girlNames=rd_b_fl.readlines()

girlNames=[name.strip().lower() for name in girlNames]

#print the message to prompt for name

print('Enter a name to see if it is a popular girls or boys name.')

while True:

#prompt and read the name

name=input('\nEnter a name to check, or \"stop\" to stop: ').lower()

# if the input is stop, then exit from the program

if name=='stop':

break

# If the girl name exits in the file,then return 1

g_count=girlNames.count(name)

# if return value greater than 0, then print message

if g_count>0:

print(name.title()+" is a popular girls name and is ranked "

+str(girlNames.index(name)+1))

# if return value greater than 0, then print message

#"Not popular name"

else:

print(name.title()+" is not a popular girls name")

## If the boy name exits in the file,then return 1

b_count=boyNames.count(name)

if b_count>0:

print(name.title()+" is a popular boys name and is ranked "

+str(boyNames.index(name)+1))

# if return value greater than 0, then print message

#"Not popular name"

else:

print(name.title()+" is not a popular boys name")

3 0
3 years ago
OMGGGGGGGGGGG chloeeeeeeeee plzzzzzzzzzz
tangare [24]

Answer:

huh y did u waste my 6 months ya gone pay for it

4 0
3 years ago
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If you boot your computer from linux live media, you will be able to use a fully-functional linux system prior to installing lin
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True except that you can't write anything.
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4 years ago
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